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Piyush Hatwalne BTech Tuition trainer in Hyderabad/>

Piyush Hatwalne

locationImg Kondapur, Hyderabad
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Details verified of Piyush Hatwalne

Identity

Education

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Tutor

I can teach each and every topics very easily and make it stronger for the students.

Languages Spoken

Marathi

English

Hindi

Education

Indian Institute of Technology, Hyderabad 2017

Bachelor of Technology (B.Tech.)

Address

Kondapur, Hyderabad, India - 500032

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Teaches

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

BTech Branch

BTech Chemical Engineering

BTech Chemical subjects

Mechanical Operations, Chemical Engineering, Energy Engineering & Technology, Fluid & Fluid Particle Systems, Inorganic And Physical Chemistry, Chemical Reaction Engineering, Mass Transfer, Catalysis And Colloidal Systems

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ICSE, IGCSE, State, International Baccalaureate, CBSE

Subjects taught

Physics, Chemistry, Social Science, Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ICSE, IGCSE, State, International Baccalaureate, CBSE

Subjects taught

Science, Mathematics, Chemistry, Social Science, Physics

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, IGCSE, ISC/ICSE, International Baccalaureate

Subjects taught

Mathematics, Chemistry, Economics, Physics

Taught in School or College

No

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, IGCSE, ISC/ICSE, International Baccalaureate

Subjects taught

Mathematics, Economics, Physics, Chemistry

Taught in School or College

No

Engineering Entrance Coaching classes

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Engineering Entrance Exams

IIT JEE Coaching Classes, BITSAT Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching, IIT JEE Integrated Coaching, IIT JEE Mains Coaching

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Chemistry , Physics

Reviews

No Reviews yet!

Answers by Piyush Hatwalne (4)

Answered on 05/12/2017 +1

Ask a Question

Post a Lesson

Assuming PQ is parallel to BC and assuming the triangle is a right angle triangle with right angle at B. The problem can be solved by equating the area of the triangles.
Answers 5 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn Tuition/Class XI-XII Tuition (PUC)

Ask a Question

Post a Lesson

Sec(120) = 1/Cos(120). Cos (120)= Cos(90+30) = - Cos(90 - 30) = -Cos(60) = 1/2. Hence, Sec (120) = -1/(1/2) = 2.
Answers 61 Comments
Dislike Bookmark

Answered on 05/12/2017 +1

Ask a Question

Post a Lesson

The atomic number of Carbon is 6, of which four are free to form bolds. Hence each carbon atom can form 4 bonds. Carbon also as High catenation power, meaning it can form long chains of carbon-carbon bonds. This is due to its ability to form sp hybrid orbitals.
Answers 5 Comments
Dislike Bookmark

Answered on 05/12/2017 +1

Ask a Question

Post a Lesson

120 W is 120 Joules per second, and 20Minutes is 1200 seconds. Hence the total energy consumed is 1200seconds*120W = 144000 Joules or 144 Kilo Joules.
Answers 10 Comments
Dislike Bookmark
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Ask a Question

Please enter your Question

Please select a Tag

Teaches

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

BTech Branch

BTech Chemical Engineering

BTech Chemical subjects

Mechanical Operations, Chemical Engineering, Energy Engineering & Technology, Fluid & Fluid Particle Systems, Inorganic And Physical Chemistry, Chemical Reaction Engineering, Mass Transfer, Catalysis And Colloidal Systems

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

Taught in School or College

No

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ICSE, IGCSE, State, International Baccalaureate, CBSE

Subjects taught

Physics, Chemistry, Social Science, Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ICSE, IGCSE, State, International Baccalaureate, CBSE

Subjects taught

Science, Mathematics, Chemistry, Social Science, Physics

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, IGCSE, ISC/ICSE, International Baccalaureate

Subjects taught

Mathematics, Chemistry, Economics, Physics

Taught in School or College

No

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, IGCSE, ISC/ICSE, International Baccalaureate

Subjects taught

Mathematics, Economics, Physics, Chemistry

Taught in School or College

No

Engineering Entrance Coaching classes

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Engineering Entrance Exams

IIT JEE Coaching Classes, BITSAT Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching, IIT JEE Integrated Coaching, IIT JEE Mains Coaching

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Chemistry , Physics

No Reviews yet!

Answers by Piyush Hatwalne

Answered on 05/12/2017 +1

Ask a Question

Post a Lesson

Assuming PQ is parallel to BC and assuming the triangle is a right angle triangle with right angle at B. The problem can be solved by equating the area of the triangles.
Answers 5 Comments
Dislike Bookmark

Answered on 05/12/2017 Learn Tuition/Class XI-XII Tuition (PUC)

Ask a Question

Post a Lesson

Sec(120) = 1/Cos(120). Cos (120)= Cos(90+30) = - Cos(90 - 30) = -Cos(60) = 1/2. Hence, Sec (120) = -1/(1/2) = 2.
Answers 61 Comments
Dislike Bookmark

Answered on 05/12/2017 +1

Ask a Question

Post a Lesson

The atomic number of Carbon is 6, of which four are free to form bolds. Hence each carbon atom can form 4 bonds. Carbon also as High catenation power, meaning it can form long chains of carbon-carbon bonds. This is due to its ability to form sp hybrid orbitals.
Answers 5 Comments
Dislike Bookmark

Answered on 05/12/2017 +1

Ask a Question

Post a Lesson

120 W is 120 Joules per second, and 20Minutes is 1200 seconds. Hence the total energy consumed is 1200seconds*120W = 144000 Joules or 144 Kilo Joules.
Answers 10 Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

X

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