Saroornagar, Hyderabad Details verified of Badrinath P✕
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English
Telugu
K U 2001
Master of Science (M.Sc.)
OSMANIA UNIVERSITY 2008
Bachelor of Education (B.Ed.)
Saroornagar, Hyderabad, India - 500060
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
16
Board
ISC/ICSE, State, CBSE
Subjects taught
Chemistry
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
16
Board
ISC/ICSE, State, CBSE
Subjects taught
Chemistry
Taught in School or College
Yes
Answered on 23/10/2018
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Like 0 
Answers 25 
Comments Answered on 20/10/2018 Learn CBSE - Class 11/Science/Chemistry/Hydrogen
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Like 0 Answers 3 Comments Answered on 19/10/2018 Learn CBSE - Class 11/Science/Chemistry/Hydrogen
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1) Answer is b i,e is an oxidising agent in(A) and reducing agent in (B).Sinse in A Iodide is oxidised as Iodine(Oxidation number is increases i,e is -1 to 0),in B Chlorine is reduced to Chloride Ion(Oxidation number is decreases i,e +1 to -1)
2) answer is b i,e is BaO2 8H2o. Because BaO2 contains peroxide linkage.
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
16
Board
ISC/ICSE, State, CBSE
Subjects taught
Chemistry
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
16
Board
ISC/ICSE, State, CBSE
Subjects taught
Chemistry
Taught in School or College
Yes
Answered on 23/10/2018
Ask a Question
Post a Lesson
Like 0 Answers 25 Comments Answered on 20/10/2018 Learn CBSE - Class 11/Science/Chemistry/Hydrogen
Ask a Question
Post a Lesson
Like 0 Answers 3 Comments Answered on 19/10/2018 Learn CBSE - Class 11/Science/Chemistry/Hydrogen
Ask a Question
Post a Lesson
1) Answer is b i,e is an oxidising agent in(A) and reducing agent in (B).Sinse in A Iodide is oxidised as Iodine(Oxidation number is increases i,e is -1 to 0),in B Chlorine is reduced to Chloride Ion(Oxidation number is decreases i,e +1 to -1)
2) answer is b i,e is BaO2 8H2o. Because BaO2 contains peroxide linkage.
Like 0 Answers 2 Comments Ask a Question
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Hyderabad
