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Sanskrit Tutors near me in Sector 10 A, Gurgaon

Select from 10 Online & Offline Sanskrit Tutors in your locality

1
Guruji Home Tuitions Sanskrit Tutors institute in Gurgaon Sponsored
Online Classes Online Classes
Classes: Sanskrit Tutors, Hindi Language and more.

Guruji provides tuition classes.

1
Sector 10 A, Gurgaon
1 yrs of Exp
Classes: Sanskrit Tutors Class 10 Tuition

I can teach every topic very easily and make it stronger for the students.

2
Sector 10 A, Gurgaon
4 yrs of Exp
Classes: Sanskrit Tutors, Class 10 Tuition and more.

Iam a teacher.i ha e an 3 uears teaching experin ed in maths and science subject.i hace engineering degree in electronics subject......my profile...

3
Sector 10 A, Gurgaon
1 yrs of Exp
Classes: Sanskrit Tutors Class 8 Tuition

I have done my B. Tech in Mechanical engineering and having more than 7 years in the manufacturing industry. Now, I have left the job and want to...

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4
Sector 10 A, Gurgaon
1 yrs of Exp
Classes: Sanskrit Tutors, Class 6 Tuition and more.

I am a home tutor .I have a degree in bachelor of science.My key skill are good communication, new and efficient ways of teaching.I am giving home...

5
Sector 10 A, Gurgaon
12 yrs of Exp
Classes: Sanskrit Tutors, Class 10 Tuition

My self Banita yadav Hindi and Sanskrit teacher.I have 10 years experience.I am working in royal public school in gurgaon.I am MA B.ed in Sanskri...

6
Sector 10 A, Gurgaon
1 yrs of Exp
Classes: Sanskrit Tutors, Makeup and more.

I am a makeup artist. I am giving home teachingn I am certified from lakme academy, Delhi. I complete my CCMA and GCMA from delhi.

7
Sector 10 A, Gurgaon
5 yrs of Exp
Classes: Sanskrit Tutors Class I-V Tuition

8
Sector 10 A, Gurgaon
12 yrs of Exp
Classes: Sanskrit Tutors, Class 11 Tuition

9
Sector 10 A, Gurgaon
1 yrs of Exp
Classes: Sanskrit Tutors Class I-V Tuition

10
Sector 10 A, Gurgaon
1 yrs of Exp
Classes: Sanskrit Tutors Class I-V Tuition

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Key highlights about Sanskrit Tutors

✅ Free Demo Class : Available
✅ Average price : INR 325/hr
✅ Tutors available : 10
✅ Class format : Online or Offline classes

FAQ

How do I find the best Sanskrit Tutors near me in Sector 10 A, Gurgaon near me?

You can browse the list of best Sanskrit Tutors tutors on UrbanPro.com. You can even book a free demo class to decide which Tutor to start classes with.

What is the typical Fee charged for Sanskrit Tutors near me in Sector 10 A, Gurgaon?

The fee charged varies between online and offline classes. Generally you get the best quality at the lowest cost in the online classes, as the best tutors don’t like to travel to the Student’s location.

Monthly Fee for 1-1 Classes

INR 3,000 - ₹ 4,800 for 12 classes per month

Hourly Fee for 1-1 Classes

INR 250 - ₹ 400

Monthly Fee for Group Classes

INR 2,400 - ₹ 3,840 for 12 classes per month

Hourly Fee for Group Classes

INR 200 - ₹ 320

Monthly Fee for Tuition at home

INR 3,600 - ₹ 4,800 for 12 classes per month

Hourly Fee for Tuition at home

INR 300 - ₹ 400

Monthly Fee for Online Tuition

INR 3,600 - ₹ 4,800 for 12 classes per month

Hourly Fee for Online Tuition

INR 300 - ₹ 400

Does joining Tuition help?

It definitely helps to join Sanskrit Tutors near me in Sector 10 A, Gurgaon, as you get the desired motivation from a Teacher to learn. If you need personal attention and if your budget allows, select 1-1 Class. If you need peer interaction or have budget constraints, select a Group Class.

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Sanskrit Tutors Questions

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"क्रोशद्व्यान्तराले" what is the meaning of this line ?

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On October 1, 1949, Chinese Communist leader Mao Zedong declared the creation of the People's Republic...

Sanskrit Tutors Lessons

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We use reported speech when we are saying what other people say, think or believe. He says he wants it. We think you are right. I believe he loves...

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Formation of double bond (oxygen molecule)

Two oxygen atoms combine to form oxygen molecule by sharing two electron pairs. Each oxygen atom (2, 6) has six electrons in the valence shell. It required...

Proof of trig double angle formula tan ( 2A )

Now tan ( A + B ) = tan A + tan B/1— tan A tan B Put B = A = tan ( A + A ) = tan ( 2A )= tan A + tan A / 1 — tan A tan A = 2 tan A / 1 —...

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