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The institute was founded by Mr Pankaj Agarwal in Nov, 2013. Mr. Pankaj Agarwal has been teaching Mathematics for over 10 years. He also used to write articles in Mathematics for IIT-Mains & IIT-Advanced in the esteemed magazine IIT Buzzword for about 18 months and his articles were appreciated by students. He has also developed many short-cuts in Mathematics that will be beneficial for students preparing for IIT-Mains & IIT-Advanced.

B-6/121 (2nd Floor)

Sector 8

Rohini, Delhi, India- 110085.

Class XI-XII Tuition (PUC)

Class Location

At the Institute

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"Find the complex number z |z+2| > |z-3|" in Tuition/Class XI-XII Tuition (PUC)

Re(z) is less than 1/2. Either substitute z = x + iy and solve. Or use the concept of perpendicular bisector.

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"Find the complex number z |z+2| > |z-3|" in Tuition/Class XI-XII Tuition (PUC)

Simply Re(z) is less than 1/2. Either use z = x + iy and solve. Or simply use the concept of perpendicular bisector.

0

| 0

"Find the approximate value of (17/81)^(1/4) using differentiation." in Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Let y = f (x) = x^(1/4). Now differentiate to find delta y in terms of delta x and then find y at the given point. Realise that (16/81)^(1/4) = 2/3. On solving you will get 65/96.

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The Wrangler's Academy address

x Class XI-XII Tuition (PUC)

Class Location

At the Institute

Class IX-X Tuition

Class Location

At the Institute

Spoken English classes

Class I-V Tuition

Class Location

At the Institute

Class VI-VIII Tuition

Class Location

At the Institute

BCom Tuition

Class Location

At the Institute

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No Reviews yet! Be the first one to Review

"Find the complex number z |z+2| > |z-3|" in Tuition/Class XI-XII Tuition (PUC)

Re(z) is less than 1/2. Either substitute z = x + iy and solve. Or use the concept of perpendicular bisector.

0

| 0

"Find the complex number z |z+2| > |z-3|" in Tuition/Class XI-XII Tuition (PUC)

Simply Re(z) is less than 1/2. Either use z = x + iy and solve. Or simply use the concept of perpendicular bisector.

0

| 0

"Find the approximate value of (17/81)^(1/4) using differentiation." in Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Let y = f (x) = x^(1/4). Now differentiate to find delta y in terms of delta x and then find y at the given point. Realise that (16/81)^(1/4) = 2/3. On solving you will get 65/96.

0

| 2

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