Bindapur Jivan Park, Delhi 
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University of delhi 2017
BSc. Mathematics
Bindapur Jivan Park, Delhi, India - 110059
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1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
ICSE, State, CBSE
Subjects taught
Physics, Biology, Social Science, Chemistry, Geography, Mathematics, Science, English, History and Civics, Economics
Taught in School or College
No
Answered on 07/08/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
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Post a Lesson
Given parameter =180 cm
i.e. 3a=180cm
a=60cm
S= perimeter /2 =90 cm
Heron formula is-
Area= [S{(S-a)+(S-b)+(S-c)}]^1/2
Where a ,b,c = side of the triangle
Here given triangle is equilateral
Therefore
a=b= c= 60cm
Now,
Area=[90{(90-60)+(90-60)+(90-60)}]^1/2
= [90{30+30+30}]^1/2
= [90×90]^1/2
= [90^2]^1/2=90cm sq.
Therefore are of the sign board =90cm sq
Like 0 
Answers 6 
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1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
ICSE, State, CBSE
Subjects taught
Physics, Biology, Social Science, Chemistry, Geography, Mathematics, Science, English, History and Civics, Economics
Taught in School or College
No
Answered on 07/08/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Ask a Question
Post a Lesson
Given parameter =180 cm
i.e. 3a=180cm
a=60cm
S= perimeter /2 =90 cm
Heron formula is-
Area= [S{(S-a)+(S-b)+(S-c)}]^1/2
Where a ,b,c = side of the triangle
Here given triangle is equilateral
Therefore
a=b= c= 60cm
Now,
Area=[90{(90-60)+(90-60)+(90-60)}]^1/2
= [90{30+30+30}]^1/2
= [90×90]^1/2
= [90^2]^1/2=90cm sq.
Therefore are of the sign board =90cm sq
Like 0 Answers 6 Comments Ask a Question
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