I teach 11th 12th maths.
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Pitampura, Delhi Details verified of Manoj Rathore✕
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Delhi university 1997
Master of Commerce (M.Com.)
212Block VP, Poorvi Pitampura, Pitampura
Pitampura, Delhi, India - 110052
Landmark: -near gopal mandir
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
20+
Board
CBSE
Subjects taught
Mathematics
Taught in School or College
No
Answered on 02/09/2019 Learn CBSE - Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.2
Ask a Question
Post a Lesson
1. sin^(-1) sin(2π/3)
Ans. Sin^(-1) sin(π-π/3)
Sin^(-1) sin(π/3)
=π/3
2. tan^(-1) tan(3π/4)
Ans. tan^(-1) tan(-π/4)
tan^(-1) tan(-π/4)
=-π/4
3. tan(sin^(-1) 3/5 + cot^(-1) 3/2)
Ans. tan (tan^(-1) 3/4 + tan^(-1) 2/3)
tan tan^(-1) (3/4+2/3)/(1-3/4×2/3)
tan tan^(-1) (9+8)/6
=17/6
Like 1 
Answers 8 
Comments Answered on 02/09/2019 Learn CBSE - Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.2
Ask a Question
Post a Lesson
1. sin^(-1) sin(2π/3)
Ans. Sin^(-1) sin(π-π/3)
Sin^(-1) sin(π/3)
=π/3
2. tan^(-1) tan(3π/4)
Ans. tan^(-1) tan(-π/4)
tan^(-1) tan(-π/4)
=-π/4
3. tan(sin^(-1) 3/5 + cot^(-1) 3/2)
Ans. tan (tan^(-1) 3/4 + tan^(-1) 2/3)
tan tan^(-1) (3/4+2/3)/(1-3/4×2/3)
tan tan^(-1) (9+8)/6
=17/6
Like 1 Answers 8 Comments Ask a Question
Also have a look at
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
20+
Board
CBSE
Subjects taught
Mathematics
Taught in School or College
No
Answered on 02/09/2019 Learn CBSE - Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.2
Ask a Question
Post a Lesson
1. sin^(-1) sin(2π/3)
Ans. Sin^(-1) sin(π-π/3)
Sin^(-1) sin(π/3)
=π/3
2. tan^(-1) tan(3π/4)
Ans. tan^(-1) tan(-π/4)
tan^(-1) tan(-π/4)
=-π/4
3. tan(sin^(-1) 3/5 + cot^(-1) 3/2)
Ans. tan (tan^(-1) 3/4 + tan^(-1) 2/3)
tan tan^(-1) (3/4+2/3)/(1-3/4×2/3)
tan tan^(-1) (9+8)/6
=17/6
Like 1 Answers 8 Comments Answered on 02/09/2019 Learn CBSE - Class 12/Mathematics/Unit III: Calculus/NCERT Solutions/Exercise 2.2
Ask a Question
Post a Lesson
1. sin^(-1) sin(2π/3)
Ans. Sin^(-1) sin(π-π/3)
Sin^(-1) sin(π/3)
=π/3
2. tan^(-1) tan(3π/4)
Ans. tan^(-1) tan(-π/4)
tan^(-1) tan(-π/4)
=-π/4
3. tan(sin^(-1) 3/5 + cot^(-1) 3/2)
Ans. tan (tan^(-1) 3/4 + tan^(-1) 2/3)
tan tan^(-1) (3/4+2/3)/(1-3/4×2/3)
tan tan^(-1) (9+8)/6
=17/6
Like 1 Answers 8 Comments Ask a Question
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