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Prathamanand Kumar

Palam Colony, Delhi, India - 110045

Prathamanand Kumar Engineering Entrance trainer in Delhi

Prathamanand Kumar

Professional Tutor + 20 Years Experience in Teachi...

Palam Colony, Delhi, India - 110045.

1 Student taught

5.0

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Overview

I am an experienced, qualified teacher and tutor with over 20 years of experience in teaching Maths, across different boards including CBSE, ICSE, and State Board. Passionate about solving mathematical problems, over the years I have helped thousands of students overcome their fear of Maths. So far, I have worked as a Teacher with Kamal public school, as a Tutor and also I have a institute named Rai Maths Academy.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

Vinoba Bhave University 1996

Master of Science (M.Sc.)

Address

Palam Colony, Delhi, India - 110045

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Engineering Entrance Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

20

Engineering Entrance Exams

BITSAT Coaching Classes, Delhi CEE Coaching Classes, IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Mains Coaching, IIT JEE Foundation Course, IIT JEE Advanced Coaching, IIT JEE Crash Course

Type of class

Regular Classes

IIT-JEE Subjects

Maths

Gallery (1)

intro video for all

Reviews

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FAQs

1. Which classes do you teach?

I teach Class 11 Tuition, Class 12 Tuition and Engineering Entrance Coaching Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 20 years.

Answers by Prathamanand Kumar (1)

Answered on 23/06/2019 Tuition

(x^3 + y^3 + z^3) - 3xyz = ( x+y+z) (x^2 + y^2 + z^2 -xy -yz- zx ).........(1) But, we have been given that ( x^2 + y^2 + z^2) = xy + yz + zx ..........(2) Put the above result in equation .....(1) We get, (x^3 + y^3 + z^3) - 3xyz = (x+y+z) ( xy + yz + zx - ( xy + yz+ zx ) So, (x^3 + y^3 + z^3) =... ...more

(x^3 + y^3 + z^3) - 3xyz  =  ( x+y+z) (x^2 + y^2 + z^2 -xy -yz- zx ).........(1)

But, we have been given that 

( x^2 + y^2 + z^2) = xy + yz + zx ..........(2)

Put the above result in equation .....(1)

We get,

(x^3 + y^3 + z^3) - 3xyz = (x+y+z) ( xy + yz + zx - ( xy + yz+ zx )

So,

(x^3 + y^3 + z^3) = 3xyz

Hence, proved

Answers 278 Comments
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Engineering Entrance Coaching classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

20

Engineering Entrance Exams

BITSAT Coaching Classes, Delhi CEE Coaching Classes, IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Mains Coaching, IIT JEE Foundation Course, IIT JEE Advanced Coaching, IIT JEE Crash Course

Type of class

Regular Classes

IIT-JEE Subjects

Maths

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

20

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

20

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

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Answers by Prathamanand Kumar (1)

Answered on 23/06/2019 Tuition

(x^3 + y^3 + z^3) - 3xyz = ( x+y+z) (x^2 + y^2 + z^2 -xy -yz- zx ).........(1) But, we have been given that ( x^2 + y^2 + z^2) = xy + yz + zx ..........(2) Put the above result in equation .....(1) We get, (x^3 + y^3 + z^3) - 3xyz = (x+y+z) ( xy + yz + zx - ( xy + yz+ zx ) So, (x^3 + y^3 + z^3) =... ...more

(x^3 + y^3 + z^3) - 3xyz  =  ( x+y+z) (x^2 + y^2 + z^2 -xy -yz- zx ).........(1)

But, we have been given that 

( x^2 + y^2 + z^2) = xy + yz + zx ..........(2)

Put the above result in equation .....(1)

We get,

(x^3 + y^3 + z^3) - 3xyz = (x+y+z) ( xy + yz + zx - ( xy + yz+ zx )

So,

(x^3 + y^3 + z^3) = 3xyz

Hence, proved

Answers 278 Comments
Dislike Bookmark

Prathamanand Kumar describes himself as Professional Tutor + 20 Years Experience in Teaching. He conducts classes in Class 11 Tuition, Class 12 Tuition and Engineering Entrance Coaching. Prathamanand is located in Palam Colony, Delhi. Prathamanand takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 20 years of teaching experience . Prathamanand has completed Master of Science (M.Sc.) from Vinoba Bhave University in 1996. HeĀ is well versed in English and Hindi.

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