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Anil Upadhyay Class 9 Tuition trainer in Delhi/>

Anil Upadhyay

A TEACHER AS FRIEND

Bakhtawar Pur, Delhi, India - 110036.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I worked in this profession for 10 years. I am feeling proud to be as Teacher. I am one who have the responsibility of the making one's future.This is my promise that I will not let you down.

Languages Spoken

Hindi Mother Tongue (Native)

Education

MJK Collage 1994

Graduate

Address

Bakhtawar Pur, Delhi, India - 110036

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

CBSE

CBSE Subjects taught

English, Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

CBSE

CBSE Subjects taught

English, Mathematics, Science

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 4 years.

Answers by Anil Upadhyay (4)

Answered on 22/01/2018 Learn CBSE/Class 10/Social Studies +1 Tuition/Class IX-X Tuition

No corporation to the British which was rule to the India. Many Indian was stop British job. Mahatama Ghandhi led this movement.
Answers 4 Comments
Dislike Bookmark

Answered on 22/01/2018 Learn CBSE/Class 10/Social Studies +1 Tuition/Class IX-X Tuition

No corporation with the British who rule India. Many Indian stopped going to their British jobs. Mahatama Ghandhi led this movement.
Answers 4 Comments
Dislike Bookmark

Answered on 22/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Given equation is: (c 2 – ab) x 2 – 2 (a 2 – bc) x + (b 2 – ac) = 0 To prove: a = 0 or a 3 + b 3 + c 3 = 3abc Proof: From the given equation, we have a = (c2 – ab) b = –2 (a 2 – bc) c = (b 2 – ac) It is being given that equation has real and equal roots ∴... ...more

Given equation is:

(c 2 – abx 2 – 2 (a 2 – bcx + (b – ac) = 0

To prove: a = 0 or a 3 + b 3 + c 3 = 3abc

Proof: From the given equation, we have

a = (c2 – ab)

b = –2 (a 2 – bc)

c = (b 2 – ac)

It is being given that equation has real and equal roots

∴ D = 0

⇒ b 2 – 4ac = 0

On substituting respective values of ab and c in above equation, we get

[–2 (a 2 – bc)]2 – 4 (c 2 – ab) (b 2 – ac) = 0

4 (a 2 – bc)2 – 4 (c 2 b 2 – ac 3 – ab 3 + a 2 bc) = 0

4 (a 4 + b 2 c 2 – 2a 2 bc) – 4 (c 2 b 2 – ac 3 – ab 3 + a 2 bc) = 0

⇒ a 4 + b 2 c 2 – 2a 2 bc – b 2 c 2 + ac 3 + ab 3 – a 2 bc = 0

⇒ a 4 + ab 3 + ac 3 –3a 2 bc = 0

⇒ a [a 3 + b 3 + c 3 – 3abc] = 0

a = 0 or a 3 + b 3 + c 3 = 3abc

Answers 6 Comments
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Answered on 22/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Let original speed of train = x km/h We know, Time = distance/speed First case: Time taken by train = 360/x hour Second case: Time taken by train its speed increase 5 km/h = 360/(x + 5) Time taken by train in first - time taken by train in 2nd case = 48 min = 48/60 hour 360/x - 360/(x +5) = 48/60... ...more

Let original speed of train = x km/h

We know,

Time = distance/speed

First case:

Time taken by train = 360/x hour

Second case:

Time taken by train its speed increase 5 km/h = 360/(x + 5)

Time taken by train in first - time taken by train in 2nd case = 48 min = 48/60 hour

360/x - 360/(x +5) = 48/60 = 4/5

360 {1/x - 1/(x +5)} = 4/5

360 ×5/4 {5/(x²+5x)}=1

450 x 5 = x² + 5x

x²+5x - 2250 = 0

x = {-5±√(25+9000)}/2

= (-5 ±√(9025))/2

=(-5 ± 95)/2

= -50, 45

But x ≠ -50 because speed doesn't negative,

So, x = 45 km/h

Hence, original speed of train = 45 km/h

Answers 2 Comments
Dislike Bookmark

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

4

Board

CBSE

CBSE Subjects taught

English, Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

4

Board

CBSE

CBSE Subjects taught

English, Mathematics, Science

Taught in School or College

No

No Reviews yet!

Answers by Anil Upadhyay (4)

Answered on 22/01/2018 Learn CBSE/Class 10/Social Studies +1 Tuition/Class IX-X Tuition

No corporation to the British which was rule to the India. Many Indian was stop British job. Mahatama Ghandhi led this movement.
Answers 4 Comments
Dislike Bookmark

Answered on 22/01/2018 Learn CBSE/Class 10/Social Studies +1 Tuition/Class IX-X Tuition

No corporation with the British who rule India. Many Indian stopped going to their British jobs. Mahatama Ghandhi led this movement.
Answers 4 Comments
Dislike Bookmark

Answered on 22/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Given equation is: (c 2 – ab) x 2 – 2 (a 2 – bc) x + (b 2 – ac) = 0 To prove: a = 0 or a 3 + b 3 + c 3 = 3abc Proof: From the given equation, we have a = (c2 – ab) b = –2 (a 2 – bc) c = (b 2 – ac) It is being given that equation has real and equal roots ∴... ...more

Given equation is:

(c 2 – abx 2 – 2 (a 2 – bcx + (b – ac) = 0

To prove: a = 0 or a 3 + b 3 + c 3 = 3abc

Proof: From the given equation, we have

a = (c2 – ab)

b = –2 (a 2 – bc)

c = (b 2 – ac)

It is being given that equation has real and equal roots

∴ D = 0

⇒ b 2 – 4ac = 0

On substituting respective values of ab and c in above equation, we get

[–2 (a 2 – bc)]2 – 4 (c 2 – ab) (b 2 – ac) = 0

4 (a 2 – bc)2 – 4 (c 2 b 2 – ac 3 – ab 3 + a 2 bc) = 0

4 (a 4 + b 2 c 2 – 2a 2 bc) – 4 (c 2 b 2 – ac 3 – ab 3 + a 2 bc) = 0

⇒ a 4 + b 2 c 2 – 2a 2 bc – b 2 c 2 + ac 3 + ab 3 – a 2 bc = 0

⇒ a 4 + ab 3 + ac 3 –3a 2 bc = 0

⇒ a [a 3 + b 3 + c 3 – 3abc] = 0

a = 0 or a 3 + b 3 + c 3 = 3abc

Answers 6 Comments
Dislike Bookmark

Answered on 22/01/2018 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Let original speed of train = x km/h We know, Time = distance/speed First case: Time taken by train = 360/x hour Second case: Time taken by train its speed increase 5 km/h = 360/(x + 5) Time taken by train in first - time taken by train in 2nd case = 48 min = 48/60 hour 360/x - 360/(x +5) = 48/60... ...more

Let original speed of train = x km/h

We know,

Time = distance/speed

First case:

Time taken by train = 360/x hour

Second case:

Time taken by train its speed increase 5 km/h = 360/(x + 5)

Time taken by train in first - time taken by train in 2nd case = 48 min = 48/60 hour

360/x - 360/(x +5) = 48/60 = 4/5

360 {1/x - 1/(x +5)} = 4/5

360 ×5/4 {5/(x²+5x)}=1

450 x 5 = x² + 5x

x²+5x - 2250 = 0

x = {-5±√(25+9000)}/2

= (-5 ±√(9025))/2

=(-5 ± 95)/2

= -50, 45

But x ≠ -50 because speed doesn't negative,

So, x = 45 km/h

Hence, original speed of train = 45 km/h

Answers 2 Comments
Dislike Bookmark

Anil Upadhyay describes himself as A TEACHER AS FRIEND. He conducts classes in Class 10 Tuition and Class 9 Tuition. Anil is located in Bakhtawar Pur, Delhi. Anil takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 4 years of teaching experience . Anil has completed Graduate from MJK Collage in 1994. He is well versed in Hindi.

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