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Aditya Verma Class 9 Tuition trainer in Delhi

Aditya Verma

MBA Graduate with Engineering background and a passion for teaching Mathematics

Vasant Kunj, Delhi, India - 110070.

Top Tutor 13 Students

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I am a Mathematics teacher providing online classes since January 2021. My strength in the subject is derived from my Engineering background which was further honed through statistical subjects while doing my MBA from the Indian School of Business in Hyderabad. My accomplishments in mathematics include 97% in CBSE Mathematics board exams and a full score of 51 in the quant section of the GMAT exam.

Intro Video

  • Class 9 Tuition

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

Indian School of Business 2019

Master of Business Administration (M.B.A.)

Address

Vasant Kunj, Delhi, India - 110070

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Teaches

Class 9 Tuition
6 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

5

Board

CBSE

Preferred class strength

One on one/ Private Tutions, Group Classes

CBSE Subjects taught

Mathematics

Experience in School or College

I have been a teacher of Mathematics for the last 5 years taking private tuitions for senior school students.

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

CBSE

CBSE Subjects taught

Mathematics

Experience in School or College

After 5+ years of corporate experience, I started my own teaching institute in 2021. My area of focus is Class 9 and Class 10 mathematics.

Taught in School or College

Yes

Teaching Experience in detail in Class 10 Tuition

I help students in preparation for CBSE Class 10 as per NCERT guidelines to enable them to be competitive in board exams. Building a mathematical intuition rather than rote based learning is my focus.

Reviews (11)

5 out of 5 11 reviews

Aditya Verma https://s3-ap-southeast-1.amazonaws.com/tv-prod/member/photo/9032410-small.jpg Vasant Kunj
5.00511
Aditya Verma
B

Class 9 Tuition

"I availed Aditya’s Math tuitions for my cousin who is in 9th class. It is very difficult to find teachers who go focus not just on problem solving/Q&A part of mathematics but also emphasise on the conceptual and derivative aspect of mathematics which can actually generate an interest in the mind of the student. Aditya is one such rare people out there who focuses on making math more interesting and engaging to the student. My cousin has totally benefited from it and Maths is now a favourite subject of his. I would totally recommend Aditya to all of you out there. "

Aditya Verma
A

Class 9 Tuition

"Aditya sir explains concepts very well. He teaches very patiently and makes the classes fun for the student. "

Aditya Verma
P

Class 9 Tuition

"Aditya Sir is very thorough in his classes and makes sure I understand the concepts properly. He is super patient when clearing any doubts which makes it easier to understand and his classes are very interactive. "

Aditya Verma
P

Class 9 Tuition

"Aditya Sir is very thorough in his explanations and makes sure you understand. The concepts making the classes a lot more fun and interactive. "

Have you attended any class with Aditya?

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

No, I don't provide a demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Answers by Aditya (1)

Answered on 28/04/2021 Learn Tuition

Let the first variable be "x." Let the second variable be "y." Define the value of x = x+y. Define the value of y = x-y. Now, define again or change the definition of the value of y = (x+y)/2; this will change the value of y to be x. Finally, change the definition of x = x-y; this will result in the... ...more
  • Let the first variable be "x."
  • Let the second variable be "y."
  • Define the value of x = x+y.
  • Define the value of y = x-y.
  • Now, define again or change the definition of the value of y = (x+y)/2; this will change the value of y to be x.
  • Finally, change the definition of x = x-y; this will result in the new value of x being y.

Hence, the value of both variables has been swapped.

Answers 281 Comments
Dislike Bookmark

Teaches

Class 9 Tuition
6 Students

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

5

Board

CBSE

Preferred class strength

One on one/ Private Tutions, Group Classes

CBSE Subjects taught

Mathematics

Experience in School or College

I have been a teacher of Mathematics for the last 5 years taking private tuitions for senior school students.

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

CBSE

CBSE Subjects taught

Mathematics

Experience in School or College

After 5+ years of corporate experience, I started my own teaching institute in 2021. My area of focus is Class 9 and Class 10 mathematics.

Taught in School or College

Yes

Teaching Experience in detail in Class 10 Tuition

I help students in preparation for CBSE Class 10 as per NCERT guidelines to enable them to be competitive in board exams. Building a mathematical intuition rather than rote based learning is my focus.

Answers by Aditya Verma (1)

Answered on 28/04/2021 Learn Tuition

Let the first variable be "x." Let the second variable be "y." Define the value of x = x+y. Define the value of y = x-y. Now, define again or change the definition of the value of y = (x+y)/2; this will change the value of y to be x. Finally, change the definition of x = x-y; this will result in the... ...more
  • Let the first variable be "x."
  • Let the second variable be "y."
  • Define the value of x = x+y.
  • Define the value of y = x-y.
  • Now, define again or change the definition of the value of y = (x+y)/2; this will change the value of y to be x.
  • Finally, change the definition of x = x-y; this will result in the new value of x being y.

Hence, the value of both variables has been swapped.

Answers 281 Comments
Dislike Bookmark

Aditya Verma describes himself as MBA Graduate with Engineering background and a passion for teaching Mathematics. He conducts classes in Class 10 Tuition and Class 9 Tuition. Aditya is located in Vasant Kunj, Delhi. Aditya takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 5 years of teaching experience . Aditya has completed Master of Business Administration (M.B.A.) from Indian School of Business in 2019. He is well versed in Hindi and English. Aditya has got 11 reviews till now with 100% positive feedback.

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