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# x And y Are Real Numbers s.t 2 < x < 3 And -8 Sujoy Das 07/02/2018 2 0 0 Question: x and y are real numbers s.t 2 < x < 3 and -8<y: A) x^2 y B) xy^2 C) 5xy   Solution:   xY^2 is postive. So out of scope X^2 Y has min value of 4 * -8 = - 32 and 5xy can have min value of 5*2* -8 = - 80 (I know they arent equal. But by approaximation it can be inferred) Also y has to be of odd degree and thn maximise x.

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