What is the explanation of Boolean's algebra (x+x').(y+1)=(x+x').1?

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(x+x').(y+1)=(x+x').1
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Tutor

'1+y' will always be true irrespective of the truth value of 'y'
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B.TECH

in OR { i.e (+) plus } operation any variable add with 1 it result always 1.. and similarly in AND { i.e (.) dot} operation if 0 comes it always result 0.
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Computer Science And Maths Teacher

We can simplify LHS and show that it is equal to RHS using Boolean laws. x+x' =1( Sum of Boolean variable and its complement is always 1) y+1=1 (Logical addition with 1 is always 1) LHS = 1x1=1(Logical multiplication of 2 true values ) RHS =1(x+x'=1 and 1x1=1) ...
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We can simplify LHS and show that it is equal to RHS using Boolean laws. x+x' =1( Sum of Boolean variable and its complement is always 1) y+1=1 (Logical addition with 1 is always 1) LHS = 1x1=1(Logical multiplication of 2 true values ) RHS =1(x+x'=1 and 1x1=1) So LHS=RHS read less
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Physics & Mathematics Expert for JEE Mains,Advanced & Olympiads with 14 yrs experience

1 + anything =1 in boolean algebra so y+1 =1 also x+x' =1
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i am a Software Engineer in capgemini at PSN,Bangalore,Whitefield and i want a part time teaching job

in digital logic "+" sign of boolean means "or" so "1+y" means "1" because in boolean "1" is for true "0" is for false.here either "y" can be "0" or "1" if we are talking only about digital logic not fuzzy logic. so "1+y" means either "True + false" Or "True+True" in both the cases answer is "True"so...
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its not possible in one step
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Teacher

Since logically 1+0=1 and 1+1=1, 1+y=1, as y can be either 0 or 1. Therefore, (x+x').(y+1)=(x+x').1
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Because Y + 1 is 1
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