What is the area of Pentagon?

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Mohit Verma

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The Area of a Regular Pentagon = 5 x Area of one Equilateral Triangle *From centre of Pentagon draw line to each corner of Pentagon which will give 5 Triangles of equal area i.e. 5 Equilateral Triangles. Hence 5 times area of one triangle gives area of Pentagon
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Mathematics, Physics, Chemistry, Electronics & Commujnication

Area of Pentagon whose vertices are (x1,y1),(x2,y2),(x3,y3),(x4,y4),(x5,y5) then Area of Pentagon=||
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Mathematics, Physics, Chemistry, Electronics & Commujnication

Area of Pentagon =|| Vertices of Pentagon is (x1,y1),(x2,y2),(x3,y3),(x4,y4),(x5,y5)
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Area of Regular Polygon = (N*S*S*Cot(180/N))/4 where N is number of sides and S is the length of each side
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I am B. Tech(Computer Science/IT) graduate

Area=(1/4)(sqrt(5(5+2sqrt(5))))a^2 where a is the side of the regular pentagon
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Tutor

A regular pentagon consists of 10 right angled triangles, as its all angles and sides are equal, area of one right angles triangle= 1/2 base into height when multiplied by 10 gives the area of the pentagon . you only need to know the side length of pentagon.
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Maths and Computer Tutor for 8,9,10,11,12

5/2(s*a)
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Maths and Computer Tutor for 8,9,10,11,12

Where 's' is the side and 'a' is apothem length of pentagon.
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MSc. B.Ed

Draw a pentagon ABCDE. Join CE. You get one triangle and a trapezium. Area of triangle=1/2 X Base X Height, and area of trapezium = Sum of length of two parallel sides / 2 X height. Area of Pentagon = Area of triangle + Area of trapezium.
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Tutor

Divide the pentagon into 5 rectangles and then calculate the area of these rectangles . Finally sum the area of these triangles.
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