5 × 1016 electrons pass across the section of a conductor in 1 minutes and 20 seconds. The current is flowing a.) 0.1 mA. b.) 1 mA. c.) 10 mA. d.) 100 mA.

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Lakshiyaa Rk

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Answer - (A) Electric Current ( I ) = Quantity of Charge (Q) time (t) Charge Q = ne (no. of electrons electrons × charge on electron ) Charge on electron = 1.6 × 10-19 C here n = 5 ×1016 t = 1min...
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Answer - (A) Electric Current ( I ) = Quantity of Charge (Q) time (t) Charge Q = ne (no. of electrons electrons × charge on electron ) Charge on electron = 1.6 × 10-19 C here n = 5 ×1016 t = 1min 20sec = 80 sec I = ne = 5 ×1016× 1.6 × 10-19 = 1016× 10-19 = 10-4 A = 103 mA = 10-1mA = 0.1mA t 80 10 104 ( 1A = 103mA ) read less
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Q=n.e, q=c.t, ne=ct, 5x10*16x1.6x10*-19=cx80, c=5x10*16x1.6x10*-19/80Amps=5x10*16x1.6x10*-19/80x10*3milli amps
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none of them is correct. correct answer is 1.01x 10to power -19 ampere.
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Charge of an electron is 1.6X10^19 Number of electron is 5X10^16 time=1minute 20sec=60sec 20sec=80sec current=(number of electron x each electron value)/time current=((5x10^16)x(1.6x10^-19))/80sec current=(8x10^-3)/80 current=0.1mili amps
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