Two long parallel conductors carry 100 A. If the conductors are separated by 20 mm, the force per meter of length of each conductor will be a.) 100 N. b.) 10 N. c.) 1 N. d.) 0.01 N.

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Software engineer

Given data: Current I1 and I2 = 100 Amps; Distance = 20 mm = 20 × 10-3 m; Force = ? We know that the force is found by the following expression. Torque developed force fT=M0 *I1 *I2/(2*(Pi)*d)=4*(Pi)*(10)^-7 *(100)^2/2*(pi)*20*(10)^-3=0.1 N
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F/l=u○/4pi)2I1i2/r 10^-7*2*10^4/20*10^-3 2*10^-3/20*10^-3=0.1N/mt
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.1N
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Tutor

none of the above.
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Home tuition for any class any course Kindly visit premiertuition.com for more infirmation
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Don't want to over express myself, just join and feel the experience.

Wrong options
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None
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Chemistry Specialist

.1N
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a
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100 n
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