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Secx+[(tanx)^2/(1+secx)]=? Sec x + = Sec x + =Sec x + = Sec x + Sec x - 1 = 2 Sec x -1

Gold medallist in maths.

sec x + =sec x + since 1+ (tan x)^2 =(sec x)^2 sec x +=sec x +(sec x - 1)= 2 sec x - 1

Note:-{2secx-1} and there is a restriction on 'x'. x not equal to(2n+1)pi.

2(Secx) -1 Learn Mathematics from an IITian

Secx+ = Secx+ = Secx+ = Secx+ = 1 Strategy: The strategy is not obvious. Multiply and divide by (sec x + tan x); use Substitution. (integral) sec x dx = (integral) sec x sec x + tan x sec x + tan x dx set u = sec x + tan x then we find du = (sec x tan x + sec2 x) dx substitute du = (sec x tan x + sec2 x) dx, u =... read more
Strategy: The strategy is not obvious. Multiply and divide by (sec x + tan x); use Substitution. (integral) sec x dx = (integral) sec x sec x + tan x sec x + tan x dx set u = sec x + tan x then we find du = (sec x tan x + sec2 x) dx substitute du = (sec x tan x + sec2 x) dx, u = sec x + tan x (integral) sec x sec x + tan x sec x + tan x dx = (integral) (sec2 x + sec x tan x) dx sec x + tan x = (integral) du u solve integral = ln |u| + C substitute back u=sec x + tan x = ln |sec x + tan x| + C read less

2 secx -1

2Secx-1

2secx-1

Sec2x - Secx

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