Length of a cube is 10 cm. If it is dipped into water by half of its height then how much weight can be placed on it so that it will not sink?

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0.5kg
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Mathematician

Since the volume of the cube = 1000 cc, the volume of water displaced by it (under the given condition) = 500 cc. Since water has a Specific Gravity of 1 The weight of water displaced will be 500 gram. This is precisely the force of buoyancy acting on the cube. Hence a weight of 500 gram or less can...
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Since the volume of the cube = 1000 cc, the volume of water displaced by it (under the given condition) = 500 cc. Since water has a Specific Gravity of 1 The weight of water displaced will be 500 gram. This is precisely the force of buoyancy acting on the cube. Hence a weight of 500 gram or less can be put on the cube to make it float without sinking. read less
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Mechanical Engineer, Mathematics, Physics

Assumption: The cube sinks to half its height due to its self weight volume of 10 cm cube is 1000 cm3 half vol. = 500 cm3 normal density of water = 1000 kg/m3 mass of water that can be displaced = 0.5 kg weight that can be supported by such displaced water = m*g assuming gravity = 9.8 m/s2 weight...
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Assumption: The cube sinks to half its height due to its self weight volume of 10 cm cube is 1000 cm3 half vol. = 500 cm3 normal density of water = 1000 kg/m3 mass of water that can be displaced = 0.5 kg weight that can be supported by such displaced water = m*g assuming gravity = 9.8 m/s2 weight that can be supported without sinking = 4.9 N read less
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By theorm, "weight of body = weight of water which is replaced by body " So, weight of water replaced by body =(10 x 10 x 10 ) x10 / 2 = 5000 kN then, 10 x 10 x 10 x unit weight of body = 5000 ( by theorm) then , unit weight of body = 5 kN / m3 for body not sink , if body...
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By theorm, "weight of body = weight of water which is replaced by body " So, weight of water replaced by body =(10 x 10 x 10 ) x10 / 2 = 5000 kN then, 10 x 10 x 10 x unit weight of body = 5000 ( by theorm) then , unit weight of body = 5 kN / m3 for body not sink , if body totaly dip in water so weight of water replaced by body = 10000 kN for totaly dip in water, weight of body + weight of another body put on previous body = 10000 5000 + weight of another body put on previous body =10000 weight of another body put on previous body = 5000 kN Ans. read less
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MTECH - IIT MADRAS

0.5 kg ... hint mass of the floating body = mass of fluid displaced (upthrust)
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Tutor

Depends on density of the cube.
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