Take Class 12 Tuition from the Best Tutors

- Affordable fees
- 1-1 or Group class
- Flexible Timings
- Verified Tutors

✕

Search in

Follow 0

Answer

A number divisible by 2 AND 3 is divisible by 6. 100/6 = 16.67 There are 16 numbers between 1 and 100 which are divisible by 6. Out of these 16 we have to select 3 numbers. The number of ways to do this is 16C3. Total sample space is selection of 3 numbers from 100 numbers. The no. of ways to...

read more A number divisible by 2 AND 3 is divisible by 6. 100/6 = 16.67 There are 16 numbers between 1 and 100 which are divisible by 6. Out of these 16 we have to select 3 numbers. The number of ways to do this is 16C3. Total sample space is selection of 3 numbers from 100 numbers. The no. of ways to do this is 100C3. So, probability of selecting 3 numbers, which are divisible by 2 and 3 i.e by 6 out of 1st 100 natural numbers is = 16C3/100C3 = 16*15*14/(100*99*98) = 0.0035 (approx... rounded off). read less

1

Comments

S = { 1, 2 3, ............, 100 } E = { 6, 12, 18, 24, .....96 } P(E) = 16C3 / 100C3 16 x 15 x 14 3 x 2 x 1 = ------------------ x ------------------ 3 x 2 x 1 100 x 99 x 98 4 x 5 = --------------- ...

read more S = { 1, 2 3, ............, 100 } E = { 6, 12, 18, 24, .....96 } P(E) = 16C3 / 100C3 16 x 15 x 14 3 x 2 x 1 = ------------------ x ------------------ 3 x 2 x 1 100 x 99 x 98 4 x 5 = --------------- 25 x 33 4 = ---------- 165 read less

0

Comments

16C3/100C3

0

Comments

Assuming you understand the basics of probability, Here sample space is 1, 2, 3, 4, ..., 99, 100 i.e. S = {1, 2, 3, 4, ..., 99, 100} so n(S) = 100 Here Event is set of numbers divisible by 2 and 3 (or we can say divisible by 6) And Event E = {6, 12, 18, 24, ...., 90, 96} i.e. n(E) = 16 So...

read more Assuming you understand the basics of probability, Here sample space is 1, 2, 3, 4, ..., 99, 100 i.e. S = {1, 2, 3, 4, ..., 99, 100} so n(S) = 100 Here Event is set of numbers divisible by 2 and 3 (or we can say divisible by 6) And Event E = {6, 12, 18, 24, ...., 90, 96} i.e. n(E) = 16 So probability of this event will be P(E) = n(E)/n(S) = 16/100 = 4/25 (or 0.16) read less

0

Comments

The number which can be divisible by 2 as well as 3 will be like (2*3)k. So any number which is multiple of 6 will get divisible by 6. From 1 to 100 there are 16 numbers which are divisible by 6. So number of ways to choose 3 from 16 is 16C3. Probability will (16C3)/100C3

0

Comments

View 15 more Answers

Related Questions

Illustrate with examples that our Constitution is not purely rigid and not purely flexible.

The amendments to certain features affecting the federal structure of Indian State requires special majority with ratification by half of the States. Provisions related to election to the President and...

how can i register as a tutor ?

Go to Premium subscription with urbanpro.com, brings more than just a form. Additional features help you reach/contact parents/students easily, manage your profiles conveniently and manage responses being received efficiently.

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a QuestionRecommended Articles

Meet Radhe Shyam Burman, an MBA Tutor from...

Radhe Shyam is a highly skilled accounts and finance trainer with 8 years of experience in teaching. Accounting is challenging for many students and that’s where Radhe Shyam’s expertise comes into play. He helps his students not only in understanding the subject but also advises them on how to overcome the fear of accounts...

Meet Urmila, an MBBS tutor from Bangalore

Urmila is a passionate teacher with over 8 years of experience in teaching. She is currently pursuing her Ph. D. She provides classes for Class 11, Class 12, MBBS and Medical tuition. Urmila began her career in teaching long before she became a teacher. She used to provide classes for foreign national students in her college...

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Looking for Class 12 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you X ### Looking for Class 12 Tuition Classes?

The best tutors for Class 12 Tuition Classes are on UrbanPro

- Select the best Tutor
- Book & Attend a Free Demo
- Pay and start Learning

The best Tutors for Class 12 Tuition Classes are on UrbanPro