A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward and so on. Each step is lm long and required ls. Plot the x-t graph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.

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5 step forward and 3 step backwards ,net displacement is 2m and take 8s Similarly for next steps ,total time taken 16s and 4m Same procedure for others up to 8m net displacement and take 32 s But afterwards ,when he walks 5 step forward he drop into pit . Because the distance from starting is 13m So...
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5 step forward and 3 step backwards ,net displacement is 2m and take 8s Similarly for next steps ,total time taken 16s and 4m Same procedure for others up to 8m net displacement and take 32 s But afterwards ,when he walks 5 step forward he drop into pit . Because the distance from starting is 13m So total time taken is 32+5=37 s read less
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