What is the value of log 9, if log 27 = 1.431?

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0.954
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log 27 = 3 log 3 = 1.431 ; log 3 = 0.477 ; log 9 = 2 log 3 = 2 x 0.477 = 0.954
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0.954
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0.954
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Mechanical engineer

log 27= 3 log 3 And log 9= 2 log 3 log 3= (log 27)/3 = 0.477 So, Log 9= 2*0.477 = 0.954
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Maths Teacher

log 27 = log 3^3 = 3 * log 3 = 1.431 Therefore, log 3 = 1.431/3 = 0.477 log 9 = log 3^2 = 2 * log 3 = 2 * 0.477 = 0.954
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diploma in computer engineering

=log 27=1.431 =log 3^3=1.431 =3log 3=1.431 =log3=1.431/3 put this into "I" equation =log 9 =log 3^2 =2log3 "I" equation =2*(1.431/3) =0.954
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