The area of triangle ABC is 15 cm sq. If ?ABC and a parallelogram ABPD are on the same base and between the same parallel lines then what is the area of parallelogram ABPD.

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30 cm sq
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2*15=30
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THE AREA OF PARALLELOGRAM IS 30 sq. UNIT. BECAUSE BY THE THEOREM, THE AREA OF PARALLELOGRAM IS TWICE THE ARE OF TRIANGLE IF BOTH HAVE SAME COMMON BASE AND LIES BETWEEN SAME PARALLEL LINES.
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ar(?ABC) = 1/2 of ar( llgm ABPD) area of parallelgram ABPD = 2 * area of triangle ABC = 30 cm sq. because triangle and parallelogram are on the same base and between same parallel lines
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ar(||gramABPD)=2×ar(∆ABC)=2×15=30 sq cm
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Area of parallelogram ABPD=2×area of ?ABC=2×15=30 sq cm since we know that AREA OF PARALLELOGRAM is twice the are of triangles if both have common base ad between same parallel lines
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Area of parallelogram ABPD=2×area of triangle ABC=2×15=30 sq cm AREA OF PARALLELOGRAM is twice the are of triangle if both have common base and between the same parallel lines.
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