What is a good timetable for studying for exams in class 9?

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Learn Mathematics +2 CBSE - Class 9

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Kishore

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5am to 7am
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daily minimum 1 hour / subject studying
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Divide you time as per your subjects and most important spend more hours in those subjects in which your are weak and lastly get time for revision.
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For class 9th student Spend atleast one hour for each subject and focussed on your weaknesses
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you should give atleast 4 hours of study. 2hours in the evening b/w 4 pm & 6pm. 2 hours in the night (time depends on your sleeping time if you sleep early in the night then give 1 hour i the morning. ****--****** MOST IMPORTANT ****--****** take only 3 subjects in a day and other 3 subjects take...
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you should give atleast 4 hours of study. 2hours in the evening b/w 4 pm & 6pm. 2 hours in the night (time depends on your sleeping time if you sleep early in the night then give 1 hour i the morning. ****--****** MOST IMPORTANT ****--****** take only 3 subjects in a day and other 3 subjects take on the next day.. & give 1 hour to your school homework. dont try to take every subject in a day. for any further information regarding academics & exam related query, you may contact me (but after 8:30pm) ------- AASPIRATION CLASSES, Moradabad read less
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Related Questions

If m and n are odd positive integers, then m2 + n2 is even, but not divisible by 4. Justify.
Since m is odd positive integer then we can write m=2a+1 and n=2b+1, such that a,b >0 m2+n2=(2a+1)^2+(2b+1)^2 = 4a^2+1+4a+4b^2+1+4b = 4a^2+4b^2+4a+4b+2 = 2(2a^2+2b^2+2a+2b+1) Above eqn is divisible by 2 but not divisible by 4.
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Find the zeroes of the quadratic polynomial x2 + 5x + 6 and verify the relationship between the zeroes and the coefficients.
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now...
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Two numbers are in the ratio 5:6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Find the numbers?
Let numbers are 5x and 6x (5x-8)/ (6x-8) = (4/5) => 5(5x-8)= 4(6x-8) => 25x-40 = 24x-32 => 25x-24x= 40-32 => x= 8 Two numbers are 5x 8= 40 and 6x8 = 48
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Find three numbers in A.P. whose sum is 21 and their product is 231.
Let, three numbers are (a-d), a, (a+d) So, (a-d)+a+(a+d)=21 => a=7 Again, (7-d)×7×(7+d)=231 => (7-d)×(7+d)=231÷7 => 7^2 - d^2 = 33=> d^2 = 49 - 33=> d^2 = 16=> d = 4 So, the numbers are 7-4= 3, 7 and 7+4=11
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If the radius of the base of a cone is doubled keeping the height same. What is the ratio of the volume of the larger cone to the smaller cone?
When we take height=h and radios of base=r then volume of cone=?r^2*h/3 if radios of the base is doubled then R=2r and height=h so, volume is =?(2r)^2*h/3 therefore, ratio of the volume of latter cone...
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