From a group of 2 boys and 3 girls, we select a child. Find the probability of this child being a girl.

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Teacher

In total there are 5 children out of which 3 are girls So the probability of selecting a girl is 3/5 or 0.6 or 60 %
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3/5
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Physics Lecturer

Probability = no. Of girls / total no. Of child Probability = 3/5.
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Certified mentor with 20+ yrs exp, guided 100+ foreign & 500+ Indian university engineering students

3c1/5c1=3/5
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Tutor

3/5
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Debate pro and maths' master

Probability = No. Of observations/total number of observations Total observation=2+3=5 Probability of child being a girl = 3/5
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Mathematics educator with 7 years of experience as a school educator as well as a tutor.

P (child being a girl) = no. of girls/ total no. students = 3/5.
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Tutor

3/5 because if only 1 girl present here then the probability will be 1/5 but presently the no.of girls are 3 out of 5 so the probability will be 3/5 that is 60%
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4/7
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Related Questions

The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle.
Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (l × b) = (16 × 8) = (128) Area of rectangle is 128
Naveen
Solve : x + y = 18; y + z = 12; z + x = 16
Let x+y=18---(1), y+z=12---(2),z+x=16---(3) Solving (2)-(3) we get y+z-z-x=12-16 y-x=-4--(4) Solving (4)+(5) we get x+y+y-x=18-4 2y=14 y=14/2=7 Substitute y value in (1) x+7=18 x=18-7=11 Substitute x value in (3) z+11=16 z=16-11=5 x=11, y=7, z=5
Deepak
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