UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Book a Free Demo

Class 10 > An athlete completes one round a circular track of...
✕

Search in

An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance covered and the displacement at the end of 2 minute and 20 seconds.

Asked by Last Modified  

55 Answers

Follow 20
Answer

Please enter your answer

Professional Tutor with 15 years of experience.

Ans: Time taken = 2 min 20 sec = 140 sec. Radius, r = 100 m. InTime to complete one round = 40 sec So, Round completed in 140 sec = 140 ÷ 40 = 3.5 (three and a half) round. Or, distance covered = 2 x 22/7 x 100 x 3.5 = 2200 m. At the end, the athlete cavers half round and will be at a distance...
read more
Ans: Time taken = 2 min 20 sec = 140 sec. Radius, r = 100 m. InTime to complete one round = 40 sec So, Round completed in 140 sec = 140 ÷ 40 = 3.5 (three and a half) round. Or, distance covered = 2 x 22/7 x 100 x 3.5 = 2200 m. At the end, the athlete cavers half round and will be at a distance = diameter of circle. ie displacement = 200m. read less
1 Comments
Dislike Bookmark

Science Tutor

200m is the answer
1 Comments
Dislike Bookmark

Classes for IX -X Mathematics & Science

Distance covered = 2198m, Displacement = 200m
2 Comments
Dislike Bookmark

Tutor

one rround circular tract=2*pi rad angular speed= w= 2xpi/40=0.157 rad/sec dispalcement , theta=w*t= 21.98 radians distance covered=140/40 X(2XpiX100)=2200m which is coveered in 40 sec distance covered in 2 min 20 sec=140sec =14/40*1257.14
Comments
Dislike Bookmark

Tutor

here radius r=100m 2min 20sec=140sec. no of complete rotation=140/40=3.5=3+1/2. so he will end up by the time 140 sec just opposite along the diagonal, so displacement = length of diameter=200 m. total distance covered=3*(2*pi*r)+pi*r=7*pi*r=2199.1 m
Comments
Dislike Bookmark

HI For a circular track : velocity(v)= circumference/time v=3.14*200/40=15.7m/s distance covered in 2min 20 sec(140sec)= velocity * time = 140*15.7=2198m 40 seconds are required to complete 1 rotation therefore in 140 seconds, rotations completed will be =140*1/40=3.5 Thus this means three complete...
read more
HI For a circular track : velocity(v)= circumference/time v=3.14*200/40=15.7m/s distance covered in 2min 20 sec(140sec)= velocity * time = 140*15.7=2198m 40 seconds are required to complete 1 rotation therefore in 140 seconds, rotations completed will be =140*1/40=3.5 Thus this means three complete rotations and one half rotation. Therefore athlete will be diametrically opposite to his position and his displacement will be equal to length of diameter i.e. = 200m read less
Comments
Dislike Bookmark

Tutor

Here r=200/2 m=100 m. 2 min 20 sec= 140 sec. No. Of complete rotation 140/40= 3.5= 3+1/2. From definition of displacement it will be diameter of the circle i.e 200 m. Total distance covered= +?r=7?r=2221.8 m.
Comments
Dislike Bookmark

In the given time athlete will complete 3.5 round so disp will be 200m and dist 2198m
Comments
Dislike Bookmark

IITian Tutor

Displacement will be 200m, while distance = 3*2*pi*100 + pi*100 = 2198m
Comments
Dislike Bookmark

M.Sc. Biomedical Genetics, B.Sc. Biotechnology

Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s...
read more
Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s ×140 s = 2198 m (b) Displacement after 2 m 20 s i.e. in 140 s Since,rotatin in 40 s=1 Motion Ex3 Therefore, in 3.5 rotations athlete will be just at the opposite side of the circular track, i.e. at a distance equal to the diameter of the circular track which is equal to 200 m. Therefore, Distance covered in 2 m 20 s = 2198 m And, displacement after 2 m 20 s = 200m 2. Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C? Answer:- Motion Ex4 Here we have, Distance from point A to B = 300 m Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s Distance from point B to C = 100 m Time taken = 1 minute = 60 s (a) Average speed and velocity from point A to B Motion Ex5 (b) Average speed and velocity from B to C Motion Ex6 Therefore,average velocity=1.66 m/s west read less
Comments
Dislike Bookmark

View 53 more Answers

Related Questions

"रुग्णतामाकर्ण्य " what is the meaning of this line ?
This in english means morbidity. Which means the condition of being diseased.
Renu
Why Indians were outraged by the Rowlatt Act?
Because it gave the givergover autocratic powers to repress political activities.
Dhanshri
0 0
9
How consumer movement will effective?
finally you will get quality product
Pavithra
0 0
6
How we can know that white light consist of 7 colours(VIBGYOR)?
Pass a white light through a prism. If you place a screen at the other side of the prism you will find the seven colours
Ushashree
0 0
9
Construct an equilateral triangle ABC of side 6 cm?
Draw a straight 6 cm line. Then take compass and by taking 6cm in compass draw an arc from one of the line which you have drawn and without disturbing the compass from the other end of the line cut the...
Sahiba

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Economic/Commercial Activities And Their Characteristics
What do you mean by economic/commercial activities? What are features of such activities?

Rajiv Vadera

0 0
0
Building own study notes
My philosophy has always been in support of active learning by encouraging students to build their own set of study notes u. Many of my students have secured good marks by creating their own notes .I...

Rudhan S.

0 0
0
Some Important Trignometry Formulae
Class X - Trignometry. In a Right angle triangle, Sineθ = perpendicular/hypotenues Sineθ= P/H Cosθ = base/hypotenues Cosθ=B/H Tanθ = perpendicular/base...

Rahul G.

0 0
0
Inertia
First of all, the word "inertia" means ''opposition'' of change or we can say that ''against'' the change. Types of Inertia: 1. Inertia of motion: If a body is in motion then it shows opposition to...

Himanshu Rishi

0 0
0
Private, Public and Joint Sector Enterprises-Class 11 NCERT, Class 9 ICSE,Commercial Studies
CBSE Std XIth Business Studies Classification of Commercial Organisations based on the ownership-

Rajiv Vadera

2 1
0

Recommended Articles

Meet Swati, a Hindi Tutor from Bangalore

Swati is a renowned Hindi tutor with 7 years of experience in teaching. She conducts classes for various students ranging from class 6- class 12 and also BA students. Having pursued her education at Madras University where she did her Masters in Hindi, Swati knows her way around students. She believes that each student...

Read full article >

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Find Grade 10 Tuition near you
Grade 10 Tuition in Delhi
Grade 10 Tuition in Bangalore
Grade 10 Tuition in Hyderabad
Grade 10 Tuition in Chennai
Grade 10 Tuition in Kolkata
Grade 10 Tuition in Mumbai
Grade 10 Tuition in Lucknow
Grade 10 Tuition in Pune
Grade 10 Tuition in Noida
Grade 10 Tuition in Gurgaon
Online Tuition Class 10

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2025 All Rights Reserved