Quest Academy

No.2, 2nd Floor, Opposite HMT Ground RT Nagar, Bangalore, India - 560032

Quest Academy photo

Platinum

Quest Academy

No.2, 2nd Floor, Opposite HMT Ground RT Nagar, Bangalore, India - 560032

17 Students taught

5.0

UrbanPro Rating

Details verified of Quest Academy

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

Quest Academy is the first of its kind institute with a focus on preparing students for JEE (Main + Advanced), and Medical entrance examinations. The institute adopts a scientific and comprehensive approach for selecting a batch of self-motivated, talented and capable students, enhancing their capabilities through continuous guidance and evaluation of their potential, and developing exhaustive and well researched content w.r.t. examinations.

THE QUEST ACADEMY METHODOLOGY
At QUEST ACADEMY, we believe that a successful classroom is one in which the student's zeal to learn is matched by the teacher's passion to teach. We lay emphasis on selecting the right set of students and providing them with coaching and personalized mentoring to help them meet their goals.

BEST OF THE BRAINS
To connect the best of the brains around is a tradition at Quest Academy now. To explore their sheer talent & to make our students gain from their time accumulated experience is something that can be considered our foremost & intense desire. Quest Academy takes immense pride on continuing to its glorious tradition of collecting the gems to create new ones.

Address

No.2, 2nd Floor, Opposite HMT Ground

RT Nagar Main Road, RT Nagar

RT Nagar, Bangalore, India - 560032

Verified Info

Phone Verified

Email Verified

Report this Profile

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Engineering Entrance Coaching classes Overview

Engineering Entrance Coaching classes

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Engineering Entrance Exams

BITSAT Coaching Classes, IIT JEE Coaching Classes

Type of class

Regular Classes, Crash Course

Gallery (5)

Values

Classroom

Courses

Classroom

Classroom

Reviews (14)

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

4.9 out of 5.0 14 reviews

4.9/514
H
18 Apr, 2018

H.S.Pooja attended Engineering Entrance Coaching

"It helped me understand the subject at a basic level through practical experiments, changed the way to approach a problem. "

P
15 Apr, 2018

PEEYUSH YADAV attended Engineering Entrance Coaching

"It's everything a student can ask for the whole package in itself, truly is one of the best institutes. I've been here since my class 10 and have never faced any problem. The faculties are kind and supportive to the fullest. If a person co-ordinates and has the same pace as that of the teachers. One can easily get admission in their dream college. The fees is also reasonable. "

P
14 Apr, 2018

Pravin Mishra attended Medical Entrance Coaching

"A great place for the preparation of X|/X||/PU|/PU||/Engineering and Medical coaching.It is one of the best place in Bangalore.The teachers over here are very friendly and easily approachable for doubts.They will teach you how to approach on the problem and how to crack the competitive exam like JEE/NEET/KCET. "

M
14 Apr, 2018

Mahima A Mehta attended Medical Entrance Coaching

"I had taken a drop for medical, then joined quest academy, where they taught me everything right from the basics, which has made me concepts clear now. Teachers here are friendly, dedicated and approachable. There are less number of students in a class so they give you personal attention and you'll be free to ask doubts. I cannot thank them enough for everything they thought me. "

Have you attended any class with Quest Academy? Write a Review

Answers by Quest Academy (25)

Answered on 04/06/2017 Tuition/Class IX-X Tuition

Newton's second law of motion describes the relationship between an object's mass and the amount of force needed to accelerate it. Newton's second law is often stated as F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)
Answers 183 Comments
Dislike Bookmark

Answered on 04/06/2017 Tuition/Class XI-XII Tuition (PUC)

Value of Tan(360 degree) = 0.0000
Answers 145 Comments
Dislike Bookmark

Answered on 25/06/2016 Tuition/Class XI-XII Tuition (PUC)

The charge on the capacitor is Q = CV = 900 1012 F 100 V = 9 108 C The energy stored in the capacitor = (1/2) CV2 = (1/2) QV = (1/2) 9 108 C 100 V = 4.5 10% J
Answers 64 Comments
Dislike Bookmark

Answered on 23/06/2016 Tuition/Class IX-X Tuition

Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity time ?distance=15.7m/s... ...more
Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s ×140 s = 2198 m (b) Displacement after 2 m 20 s i.e. in 140 s Since,rotatin in 40 s=1 Motion Ex3 Therefore, in 3.5 rotations athlete will be just at the opposite side of the circular track, i.e. at a distance equal to the diameter of the circular track which is equal to 200 m. Therefore, Distance covered in 2 m 20 s = 2198 m And, displacement after 2 m 20 s = 200m 2. Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C? Answer:- Motion Ex4 Here we have, Distance from point A to B = 300 m Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s Distance from point B to C = 100 m Time taken = 1 minute = 60 s (a) Average speed and velocity from point A to B Motion Ex5 (b) Average speed and velocity from B to C Motion Ex6 Therefore,average velocity=1.66 m/s west
Answers 59 Comments
Dislike Bookmark

Quest AcademyDirections

x
Engineering Entrance Coaching classes 5.0

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Engineering Entrance Exams

BITSAT Coaching Classes, IIT JEE Coaching Classes

Type of class

Regular Classes, Crash Course

Class 11 Tuition 5.0

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Physics, Mathematics, Chemistry, Biology

State Syllabus Subjects taught

Physics, Biology, Chemistry, Mathematics

Class 12 Tuition 5.0

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Board

State, CBSE

CBSE Subjects taught

Physics, Mathematics, Chemistry, Biology

State Syllabus Subjects taught

Physics, Biology, Chemistry, Mathematics

Medical Entrance Coaching classes 5.0

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Teaches for following exams

AIIMS Coaching, AIPMT Coaching

Type of class

Regular Classes, Crash Course

Class 9 Tuition 5.0

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Board

CBSE

CBSE Subjects taught

Science, Mathematics, English

Class 10 Tuition 5.0

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Board

CBSE

CBSE Subjects taught

Science, Mathematics, English

CET Coaching classes 5.0

Class Location

At the Institute

Online (video chat via skype, google hangout etc)

Subjects

Mathematics, Physics, Biology, Chemistry

Class type catered to

Crash course, Integrated coaching classes, Regular Classes

Answers by Quest Academy (25)

Answered on 04/06/2017 Tuition/Class IX-X Tuition

Newton's second law of motion describes the relationship between an object's mass and the amount of force needed to accelerate it. Newton's second law is often stated as F=ma, which means the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)
Answers 183 Comments
Dislike Bookmark

Answered on 04/06/2017 Tuition/Class XI-XII Tuition (PUC)

Value of Tan(360 degree) = 0.0000
Answers 145 Comments
Dislike Bookmark

Answered on 25/06/2016 Tuition/Class XI-XII Tuition (PUC)

The charge on the capacitor is Q = CV = 900 1012 F 100 V = 9 108 C The energy stored in the capacitor = (1/2) CV2 = (1/2) QV = (1/2) 9 108 C 100 V = 4.5 10% J
Answers 64 Comments
Dislike Bookmark

Answered on 23/06/2016 Tuition/Class IX-X Tuition

Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity time ?distance=15.7m/s... ...more
Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m Time of one rotation = 40s Time after 2m20s = 2 x 60s + 20s = 140s Distance after 140 s = ? Displacement after 140s =? Motion Ex1 Motion Ex2 (a) Distance after 140s We know that,distance=velocity ×time ?distance=15.7m/s ×140 s = 2198 m (b) Displacement after 2 m 20 s i.e. in 140 s Since,rotatin in 40 s=1 Motion Ex3 Therefore, in 3.5 rotations athlete will be just at the opposite side of the circular track, i.e. at a distance equal to the diameter of the circular track which is equal to 200 m. Therefore, Distance covered in 2 m 20 s = 2198 m And, displacement after 2 m 20 s = 200m 2. Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C? Answer:- Motion Ex4 Here we have, Distance from point A to B = 300 m Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s Distance from point B to C = 100 m Time taken = 1 minute = 60 s (a) Average speed and velocity from point A to B Motion Ex5 (b) Average speed and velocity from B to C Motion Ex6 Therefore,average velocity=1.66 m/s west
Answers 59 Comments
Dislike Bookmark

Enquire

Load More

Quest Academy conducts classes in CET Coaching, Class 10 Tuition and Class 11 Tuition. It is located in RT Nagar, Bangalore. It takes Regular Classes- at the Institute. It has got 14 reviews till now with 100% positive feedback.

X

Post your Learning Need

Let us shortlist and give the best tutors and institutes.

or

Send Enquiry to Quest Academy

Let Quest Academy know you are interested in their class

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 25 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 6.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more