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A dice is thrown once. Find the probability of getting a prime number.

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Probability is the ratio of the desired possibility to all possible possibilities. In this case the desired probability is either 1or 3 or 5. So there are 3 desired possibilities. All possible possibilities when a dice is thrown are 1,2,3,4,5,6 or 6. The probability = 3/6 = 1/2 or 0.5 Ans
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Probability is the ratio of the desired possibility to all possible possibilities. In this case the desired probability is either 1or 3 or 5. So there are 3 desired possibilities. All possible possibilities when a dice is thrown are 1,2,3,4,5,6 or 6. The probability = 3/6 = 1/2 or 0.5 Ans read less
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Mathematics Professor

A dice is thrown once. Total no. of outcomes=6 Out of 6 outcomes there are three prime numbers 2,3,5 No. of favourable outcomes=3 Required probability=no.of favourable outcomes/Total no. of outcomes =3/6=1/2
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Total number of possibilities are 6 Let E be the event of getting a prime number Now number of possibilities favour to E are 3 Probability of getting a prime number is 3/6=1/2
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Number of possible outcomes of dice={1,2,3,4,5,6} Total no. of outcomes=6 prime no. of dice={2,3,5} Total prime no. of dice= 3 probability of prime no. = No. of outcomes on prime no./Total no. of outcomes= 3/6=1/2
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Prime number is a number which have exactly two divisors 1 and itself. We do not consider negative to be prime unless provided. Si duce have numbers from 1 to 6 consisting onlybthree primes 2,3 and 5. Probability of ocuuring them is total no. Of prime by total number of possible outcome ie 3/6=1/2
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Math Magician

In a dice thrown once, there 1, 2, 3, 4, 5, 6 outcomes. Among them 2, 3, 5 is prime numbers. So probability is 3/6 = 1/2.
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