Applications of Derivatives (AOD) uses derivatives to study the behaviour of functions—whether a quantity is increasing or decreasing, where it reaches maximum or minimum values, how curves behave, and how to solve optimization problems.
1. Rate of Change of Quantities
If y=f(x), then
dxdyrepresents the rate of change of y with respect to x.
Example
If
A=πr2then
drdA=2πrThis represents the rate of change of the area of a circle with respect to its radius.
Chain Rule in Rate of Change
If both quantities depend on time t:
y=f(x),x=g(t)then
dtdy=dxdy⋅dtdxImportant applications
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Rate of change of area
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Rate of change of volume
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Speed and acceleration
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Growth and decay
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Expanding circle or sphere
Example: Area of a circle
A=πr2If
dtdr=3 cm/sfind the rate of change of area when r=5.
dtdA=2πrdtdr=2π(5)(3)dtdA=30π cm2/s2. Increasing and Decreasing Functions
Let f(x) be differentiable in an interval.
Increasing Function
If
f′(x)>0then f(x) is increasing in that interval.
Decreasing Function
If
f′(x)<0then f(x) is decreasing in that interval.
Constant Function
If
f′(x)=0throughout an interval, then the function is constant there.
Steps to Find Increasing/Decreasing Intervals
Step 1
Find
f′(x)Step 2
Find critical points by solving
f′(x)=0Also consider points where f′(x) does not exist.
Step 3
Divide the domain into intervals.
Step 4
Check the sign of f′(x).
| Sign of f′(x) | Function |
|---|---|
| + | Increasing |
| − | Decreasing |
Example
f(x)=x3−3xDifferentiate:
f′(x)=3x2−3=3(x2−1)=3(x−1)(x+1)Critical points:
x=−1,x=1Now check signs:
| Interval | Sign of f′(x) |
|---|---|
| (−∞,−1) | + |
| (−1,1) | − |
| (1,∞) | + |
Therefore:
f(x) is increasing on (−∞,−1)∪(1,∞)f(x) is decreasing on (−1,1)3. Critical Points
A value x=c is called a critical point if:
f′(c)=0or
f′(c) does not existprovided f(c) exists.
Critical points are important because maximum and minimum values usually occur at such points.
4. Local Maximum and Local Minimum
Local Maximum
A function has a local maximum at x=a if
f(a)>f(x)for all nearby values of x.
Graphically:
↗Maximum↘The function changes from:
Increasing→DecreasingTherefore:
f′(x):+→−Local Minimum
A function has a local minimum at x=a if
f(a)<f(x)for all nearby values of x.
Graphically:
↘Minimum↗The function changes from:
Decreasing→IncreasingTherefore:
f′(x):−→+5. First Derivative Test
Suppose f′(a)=0.
Check the sign of f′(x) on both sides of a.
Case 1
+→−Then:
Local Maximum at x=aCase 2
−→+Then:
Local Minimum at x=aCase 3
+→+No maximum or minimum.
Case 4
−→−No maximum or minimum.
Summary
| Sign change of f′(x) | Result |
|---|---|
| +→− | Local Maximum |
| −→+ | Local Minimum |
| +→+ | Neither |
| −→− | Neither |
6. Second Derivative Test
Suppose
f′(a)=0Then calculate:
f′′(a)If
f′′(a)<0then f(a) is a local maximum.
If
f′′(a)>0then f(a) is a local minimum.
If
f′′(a)=0the test fails, and we must use another method.
Example
Find the maximum and minimum values of
f(x)=x3−3xStep 1: First derivative
f′(x)=3x2−33x2−3=0x2=1x=±1Step 2: Second derivative
f′′(x)=6xAt x=−1:
f′′(−1)=−6<0Therefore, local maximum.
f(−1)=(−1)3−3(−1)=2Local maximum=2At x=1:
f′′(1)=6>0Therefore, local minimum.
f(1)=1−3=−2Local minimum=−27. Absolute Maximum and Minimum
These are also called absolute extrema.
For a function f(x) on a closed interval [a,b]:
Steps
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Find f′(x).
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Find critical points inside (a,b).
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Calculate f(x) at:
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Critical points
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x=a
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x=b
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Compare all values.
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