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Abdul, while driving to school, computes the average speed for his trip to be 20 km h−1. On his return trip along the same route, there is less traffic and the average speed is 30 km h−1. What is the average speed for Abdul’s trip?

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Case I: While driving to school Average speed of Abdul’s trip = 20 km/h Total distance = Distance travelled to reach school = d Let total time taken = t1 …(i) Case II: While returning from school Total distance = Distance travelled while returning from school = d Now,total time taken...
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Case I: While driving to school

Average speed of Abdul’s trip = 20 km/h

Total distance = Distance travelled to reach school = d

Let total time taken = t1

 …(i)

Case II: While returning from school

Total distance = Distance travelled while returning from school = d

Now,total time taken = t2

30=dt2t2=d30  ..... (ii)30=dt2t2=d30  ..... (ii)

 

Where,

Total distance covered in the trip = d + d = 2d

Total time taken, t = Time taken to go to school + Time taken to return to school

t1 + t2

From equations (i) and (ii),

Average Speed=2dd20+d30=23+260Average Speed=1205=24 m/sAverage Speed=2dd20+d30=23+260Average Speed=1205=24 m/s

Hence, the average speed for Abdul’s trip is 24 m/s.

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Graduate with 1 year experience of tutoring.

Let distance=dTime = t1 for goingTime= t2 for coming backt1=d/20t2=d/30Total distance=2dTotal time = t1+t2Avg speed = distance/time = 2d/(d/20 + d/30) = 24 m/s
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Let distance=d
Time = t1 for going
Time= t2 for coming back
t1=d/20
t2=d/30
Total distance=2d
Total time = t1+t2
Avg speed = distance/time
                    = 2d/(d/20 + d/30)
                    = 24 m/s

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