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Class 9 Tuition Fees

Estimated Fees in India

₹ 300 to ₹ 400 per hour

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Top Ranked Tutors & Institutes for Class 9 Tuition with their fees

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Sanjeev Kumar

Uttam Nagar,Delhi

₹ 6,000 per month

I am the best for math and science . if you take demo u can judge my knowledge.

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Achintya Mondal

Sahaganj,Chinsurah

₹ 1,500 per month

A former Govt. School Teacher and a first class English honours, having 11 years of experience in teaching English Language and Literature to students ranging from classes V to XII of all boards. For demo, visit my Youtube Channel 'Ek Cup English & More...' by clicking on the following links and watch out my classes on a few topics from English Language.

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Abhishek Sharma

New Sainik Colony,Meerut

₹ 2,500 per month

I have an experience of 5 years in Home tutoring and very well know how to tackle with the problems those students are facing these days. I can teach each and every topic very easily and make it stronger for the students.

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Nilanjan Das

Thakurpukur,Kolkata

₹ 1,500 per month

I am teaching for 3 years and I being a student of ICSE board know the question pattern very well..science is my passion :)

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Pritesh Shukla

Jhabua,Jhabua

₹ 5,500 per month

6 years experience in teaching.

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Ravishankar Kumar

Itahad Nagar,Amritsar

₹ 4,000 per month

I have one year experience in teaching field in all classes science field.

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Top Questions about Class 9 Tuition Fees

Answered on 01/10/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.2

Surendra Kumar Saini

maths n science

S semiperimeter=(35+28+9)2=<36 area of one tile =√36(36_35)(36_28)(36_9)= 6*1* 14.7 = 88.2 square cm approximately. Area of 16 such tiles = 88.2*16= 1411.2sq.cm cost of polishing is 1411.2*1/2 = 705.60₹
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Answered on 22/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1

Reetika

Given,Side a=18cmSide b=10cmPerimeter=42cm=a+b+c:. Putting value42=18+10+c42=28+c42-28=c14=cNow,S=(a+b+c)/2:. Putting valueS=42/2S=21Now according to Heron's formula-Area of a triangle=√{s(s-a)(s-b)(s-c)}:. Putting value=√{21(21-18)(21-10)(21-14)}=√{21(3)(11)(7)}=√4851=21&radi... read more

Given,
Side a=18cm
Side b=10cm
Perimeter=42cm=a+b+c
:. Putting value
42=18+10+c
42=28+c
42-28=c
14=c
Now,
S=(a+b+c)/2
:. Putting value
S=42/2
S=21
Now according to Heron's formula-
Area of a triangle
=√{s(s-a)(s-b)(s-c)}
:. Putting value
=√{21(21-18)(21-10)(21-14)}
=√{21(3)(11)(7)}
=√4851
=21√11cm²

read less
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Answered on 19/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1

Manoj Kumar

Area painted in colour = √16 ( 16 - 15 ) ( 16 - 11 ) ( 16 - 6 ) = √16 × 5 × 10 = 20√2m²
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