Estimated Fees in India
₹ 300 to ₹ 400 per hour
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I am the best for math and science . if you take demo u can judge my knowledge.
A former Govt. School Teacher and a first class English honours, having 11 years of experience in teaching English Language and Literature to students ranging from classes V to XII of all boards. For demo, visit my Youtube Channel 'Ek Cup English & More...' by clicking on the following links and watch out my classes on a few topics from English Language.
I have an experience of 5 years in Home tutoring and very well know how to tackle with the problems those students are facing these days. I can teach each and every topic very easily and make it stronger for the students.
I am teaching for 3 years and I being a student of ICSE board know the question pattern very well..science is my passion :)
6 years experience in teaching.
I have one year experience in teaching field in all classes science field.
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₹ 300 to ₹ 500
₹ 300 to ₹ 500
₹ 300 to ₹ 500
₹ 300 to ₹ 400
₹ 300 to ₹ 500
₹ 300 to ₹ 500
Answered on 01/10/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.2
Surendra Kumar Saini
maths n science
Answered on 22/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Reetika
Given,
Side a=18cm
Side b=10cm
Perimeter=42cm=a+b+c
:. Putting value
42=18+10+c
42=28+c
42-28=c
14=c
Now,
S=(a+b+c)/2
:. Putting value
S=42/2
S=21
Now according to Heron's formula-
Area of a triangle
=√{s(s-a)(s-b)(s-c)}
:. Putting value
=√{21(21-18)(21-10)(21-14)}
=√{21(3)(11)(7)}
=√4851
=21√11cm²
Answered on 19/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Manoj Kumar
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