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Class 9 Tuition Fees

Estimated Fees in India

₹ 300 to ₹ 400 per hour

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Top Ranked Tutors & Institutes for Class 9 Tuition with their fees

Urvish Khira photo

Urvish Khira

Madhapar,Rajkot

₹ 6,000 per month

Naveen Kumar Pathak photo

Naveen Kumar Pathak

Laxmi Nagar Block D,Delhi

₹ 5,000 per month

I have done my graduation from Lalit Narayan Mithila University which belongs to Bihar. Actualy i started teaching at 2015 upto 10th class i teach only Mathematics because my passion for reading and teaching only Mathematics because of i love teaching profession.

Lakshmi Narayana P photo

Lakshmi Narayana P

J P Nagar,Bangalore

₹ 10,000 per month

Aloke Banerjee photo

Aloke Banerjee

Behala,Kolkata

₹ 6,000 per month

Has been coaching and training students of various backgrounds to resounding success in school exams, boards and various competitive exams.

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Deepak Kumar Tiwari

Gomtinagar,Lucknow

₹ 5,000 per month

I can teach each and every topics very easily and make it stronger for the students.

Piyush Chauhan photo

Piyush Chauhan

Greater Noida West Gaur,Noida

₹ 3,000 per month

PCMB professional with more than 4 years of experience with strong analytical skills and proven record of academic and professional success. Responsibilities: 1.Handled mathematics, Physics Chemistry and Biology classes 2. Implemented stimulating lessons to engage studentsâ?? attention and interest, allowing them to develop a passion for the subject 3. Utilized several teaching methods and techniques to guarantee the solid understanding of concepts introduced and taught 4. Offered after-school tutoring to aid struggling students to improve their academic performance. Strengths 1. Particularly adept at the creation of a stimulating learning environment for students to study in 2. Possess a genuine enthusiasm and passion for teaching math 3. Knowledge of online learning platforms and how they assist students with learning outside of the classroom 4. Excellent subject knowledge 5. Proficient in the use of new media such as the internet to promote interactive learning 6. Competent in the use of the latest teaching methods and techniques 7. Admirable ability to maintain high standards of discipline and behavior in the classroom while maintaining an approachable demeanor 8. Outstanding classroom management skills 9. Willingness to go the extra mile and stay after class as needed 10. Clever use of innovative and resourceful teaching methods to suit the special needs of an individual or group 11. Willingness to supervise extracurricular student activities and after-school events.

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Top Questions about Class 9 Tuition Fees

Lesson Posted on 19 Apr Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/Maths Geometry concepts on prooving geometrical theorems

Addition and subtraction of variable

Shivam Verma

I have been teaching Mathematics and Science for the past nine years, gaining extensive experience in...

https://vz-3ad30922-ba4.b-cdn.net/1985e219-0893-4696-8e32-802ffdca2fba/play_480p.mp4
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Answered on 01/10/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.2

Surendra Kumar Saini

maths n science

S semiperimeter=(35+28+9)2=<36 area of one tile =√36(36_35)(36_28)(36_9)= 6*1* 14.7 = 88.2 square cm approximately. Area of 16 such tiles = 88.2*16= 1411.2sq.cm cost of polishing is 1411.2*1/2 = 705.60₹
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Answered on 22/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1

Reetika

Given,Side a=18cmSide b=10cmPerimeter=42cm=a+b+c:. Putting value42=18+10+c42=28+c42-28=c14=cNow,S=(a+b+c)/2:. Putting valueS=42/2S=21Now according to Heron's formula-Area of a triangle=√{s(s-a)(s-b)(s-c)}:. Putting value=√{21(21-18)(21-10)(21-14)}=√{21(3)(11)(7)}=√4851=21&radi... read more

Given,
Side a=18cm
Side b=10cm
Perimeter=42cm=a+b+c
:. Putting value
42=18+10+c
42=28+c
42-28=c
14=c
Now,
S=(a+b+c)/2
:. Putting value
S=42/2
S=21
Now according to Heron's formula-
Area of a triangle
=√{s(s-a)(s-b)(s-c)}
:. Putting value
=√{21(21-18)(21-10)(21-14)}
=√{21(3)(11)(7)}
=√4851
=21√11cm²

read less
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