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The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter?

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Let ABCD be a rhombus (all sides are of equal length) and its diagonals, AC and BD, are intersecting each other at point O. Diagonals in a rhombus bisect each other at 90º. It can be observed that By applying Pythagoras theorem in ΔAOB, OA2 + OB2 = AB2 82 + 152 = AB2 64 + 225 = AB2 289 =...
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Let ABCD be a rhombus (all sides are of equal length) and its diagonals, AC and BD, are intersecting each other at point O. Diagonals in a rhombus bisect each other at 90º. It can be observed that

By applying Pythagoras theorem in ΔAOB,

OA2 + OB2 = AB2

82 + 152 = AB2

64 + 225 = AB2

289 = AB2

AB = 17

Therefore, the length of the side of rhombus is 17 cm.

Perimeter of rhombus = 4 × Side of the rhombus = 4 × 17 = 68 cm

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