What is the area of triangle ABC if the angle sinA = 2/bc, sin B = 2/ac, sinC = 2/ab?

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Sarvajeet Kumar

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The area of triangle ABC =(1/2).a.b. sinC=(1/2).b.c. sinA=(1/2).c.a. sinB.
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The area of triangle ABC =(1/2).a.b. sinC=(1/2).b.c. sinA=(1/2).c.a. sinB=1.
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