Length of major axis 26, foci (5, 0) find the equation for the ellipse that satisfies the given condition?

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length of major axis 2a=26; a=13; f=5; (square of f)=(square of a)-(square of b); 25=169-(square of b); (square of b)=169-25; b=12; the (sauare of x)/(169)-(square of y)/(144)=1
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The length of major axis 2a=26; a=13; ae=5; So, e=5/13 square of b=(square of a)(1-(square of e)) So, b=12; square of (x/13)-square of (y/12)=1. (square of f)=(square of a)-(square of b); 25=169-(square of b); (square of b)=169-25; b=12; the (square of x)/(169)-(square of y)/(144)=1.
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