A point pole has a strength of 4? × 10-4 weber. The force in newtons on a point pole of 4? × 1.5 × 10-4 weber placed at a distance of 10 cm from it will be A.) 20 N. B.) 15 N. C.) 7.5 N. D.) 3.75 N.

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Kumar Upendra Akshay

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Given data: Pole strength m1 = 4? × 10-7 Weber; m2 = 4? × 1.5 × 10-4; r = 10 cm. We know that the force is found by the below expression, F = 15 N
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Ans is B Pole strength m1 = 4?*10^-7 Weber; m2 = 4?*1.5 * 10^-4 Wb; d = 10 cm =10*10^-2m We know that the force is found by the below expression, F = m1m2/4??0d2 solve this getting 15 N
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B) 15 N
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20N
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