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# Cystic Fibrosis is the most common generic disease in white european and american populations.It results from one of a nmber of mutations in a single gene that codes for a protien involved in the transport of salts in the cells of the body. The cystic fibrosis gene is described as recessive , which means that individuals with only one copy of the gene so called carriers , show no symptoms of the disease and manny be unaware that they carry the gene. Individuals with two copies of the faculty CF gene will show symptom of the condition. Among white europeons,the probability of being a carrier is 1/25. For a child whose parents are both carriers, the probability of inheriting a copy of the CF gene from both parents is 1/4. a)What is the probability that any two white Europeans planning to have a child together would both be carriers? b) What is the probability of the child having cystic fibrosis?

CBSE Maths for Science stream

a) Probability of any two white Europeans planning to have a child together would both be carriers = (1/25) (1/25) = 1/ 625 b) Probability of the child having cystic fibrosis = (1/625) (1/4) = 1/2500

Doctor who loves teaching and enhancing the future of your kids

Dear kulwinder the answer to ur first question is that u have already stated 1/25 Europeans. and every 1 child out of 4 can have the chances of having the nasty disease.

Tutor

a) 1/625

I agree with Anil.

Gold Medalist

Thanks for this nice question. Its important to arrange a class to gather a sound knowledge. Because transmission of allels are associated with recombination. So, please attend class and make it clear.... Dr. P. majumder

math magician

A) 1/50

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