What is the pressure inside the drop of mercury of radius 3.00 mm at room temperature? Surface tension of mercury at that temperature (20°C) is 4.65 × 10–1 N m–1. The atmospheric pressure is 1.01 × 105 Pa. Also give the excess pressure inside the drop.

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The pressure inside the drop of mercury of radius 3.00 mm at room temperature- Radius of the mercury drop, r = 3.00 mm = 3 × 10–3 m Surface tension of mercury, S = 4.65 × 10–1 N m–1 Atmospheric pressure, P0 = 1.01 × 105 Pa Total pressure inside the mercury drop =...
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The pressure inside the drop of mercury of radius 3.00 mm at room temperature- Radius of the mercury drop,r= 3.00 mm = 3 × 10–3m Surface tension of mercury,S= 4.65 × 10–1N m–1 Atmospheric pressure,P0= 1.01 × 105Pa Total pressure inside the mercury drop = Excess pressure inside mercury + Atmospheric pressure = 1.0131 × 105 = 1.01 ×105Pa Excess pressure = 310 Pa read less
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