Calculate the pH of the following solutions: a) 2 g of TlOH dissolved in water to give 2 litre of solution. b) 0.3 g of Ca(OH)2 dissolved in water to give 500 mL of solution. c) 0.3 g of NaOH dissolved in water to give 200 mL of solution. d) 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution.

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(a) For 2g of TlOH dissolved in water to give 2 L of solution: (b) For 0.3 g of Ca(OH)2 dissolved in water to give 500 mL of solution: (c) For 0.3 g of NaOH dissolved in water to give 200 mL of solution: (d) For 1mL of 13.6 M HCl diluted with water to give 1 L of solution: 13.6 × 1 mL = M2...
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(a) For 2g of TlOH dissolved in water to give 2 L of solution: (b) For 0.3 g of Ca(OH)2 dissolved in water to give 500 mL of solution: (c) For 0.3 g of NaOH dissolved in water to give 200 mL of solution: (d) For 1mL of 13.6 M HCl diluted with water to give 1 L of solution: 13.6 × 1 mL = M2 × 1000 mL (Before dilution) (After dilution) 13.6 × 10–3 = M2 × 1L M2 = 1.36 × 10–2 [H+] = 1.36 × 10–2 pH = – log (1.36 × 10–2) = (– 0.1335 + 2) = 1.866 ∼ 1.87 read less
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