A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?

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Radius of the hoop, r = 2 m Mass of the hoop, m = 100 kg Velocity of the hoop, v = 20 cm/s = 0.2 m/s Total energy of the hoop = Translational KE + Rotational KE Moment of inertia of the hoop about its centre, I = mr2 The work required to be done for stopping the hoop is equal to the total energy of...
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Radius of the hoop,r= 2 m Mass of the hoop,m= 100 kg Velocity of the hoop,v= 20 cm/s = 0.2 m/s Total energy of the hoop = Translational KE + Rotational KE Moment of inertia of the hoop about its centre,I=mr2 The work required to be done forstopping the hoop is equal to the total energy of the hoop. ∴Required work to be done,W=mv2= 100 × (0.2)2= 4 J read less
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