To find Pythagorean triplets, we can try with 2m,m^2-1, and m^2+1Since (2m)^2+(m^2-1)^2=4m^2+m^4-2m^2+1=m^4+2m^2+1=(m^2+1)^2Example-Find Pythagorean triplets whose one number is 6Let us try with 2m=6,...
Question: Solution: Concept = if a cicrcle is inscribed, sum of parallel sides= sum of non parallel sides. x, 4x. So each of non parallel sides = 5x/2 So 10x...