The radii of two circles are 8 cm and 6 cm respectively. Find the radius of the circle having area equal to the sum of the areas of the two circles.The figure depicts an archery target marked with its five scoring regions from the centre outwards as Gold, Red, Blue, Black and White. The diameter of the region representing Gold score is 21 cm and each of the other bands is 10.5 cm wide. Find the area of each of the five scoring regions.

Radius (r1) of 1stcircle = 8 cm Radius (r2) of 2ndcircle = 6 cm Let the radius of 3rdcircle ber. Area of 1stcircle Area of 2ndcircle Given that, Area of 3rdcircle = Area of 1stcircle + Area of 2ndcircle However, the radius cannot be negative. Therefore, the radius of the circle having area equal to the sum of the areas of the two circles is 10 cm. Radius (r1) of gold region (i.e., 1stcircle) Given that each circle is 10.5 cm wider than the previous circle. Therefore, radius (r2) of 2ndcircle = 10.5 + 10.5 21 cm Radius (r3) of 3rdcircle = 21 + 10.5 = 31.5 cm Radius (r4) of 4thcircle = 31.5 + 10.5 = 42 cm Radius (r5) of 5thcircle = 42 + 10.5 = 52.5 cm Area of gold region = Area of 1stcircle Area of red region = Area of 2ndcircle − Area of 1stcircle Area of blue region = Area of 3rdcircle − Area of 2ndcircle Area of black region = Area of 4thcircle − Area of 3rdcircle Area of white region = Area of 5thcircle − Area of 4thcircle Therefore, areas of gold, red, blue, black, and white regions are 346.5 cm2, 1039.5 cm2, 1732.5 cm2, 2425.5 cm2, and 3118.5 cm2respectively. read less