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Class 10 > Learn Mathematics > Had Ravita scored 10 more marks in her Mathematics...
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Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?

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CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

9(x+10)= x² X=-6 ,15 X=15 (as -6 not possible)
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CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

9(x+10)= x² X=-6 ,15 X=15 (as -6 not possible)
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CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

9(x+10)= x² X=-6 ,15 X=15 (as -6 not possible)
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Let's assume the marks obtained by Ravita are x. According to the statement, 9(x+10) = x^2 9x +90 = x^2 x^2-9x-90 = 0 which is in the form of ax^2+bx+c=0 x=(-b±?(b^2-4ac))/2a, x=9±?(81+360))/2, x=(9+21)/2, x= 15 if x = (9-21)/2, x= -6 Assuming the positive narks scored, she scored 15 marks.
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