A wire is 1m long, 0.2mm in diameter and has resistance of 10?. Calculate its resistivity.

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R=rs(l/A) ; R -resistance. rs - resistivity, l - length of the wire, A - Area of cross-section of the wire A=∏(r^2) ; Area of the cross-section; r-radius rs=(R*A)/l rs=(10*3.14*10^-8)/1 Resitivity=31.4*10^-8
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R=kl/A Where k=restivity,l=length,A=area herel=1m A=pi.r^2=3.14*10^-8 hence restivity k=R*A/l k=3.14*10^-7 ohm.m
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R=P(l/A), R denotes resistance of wire P denotes resistivity, l denotes length of wire, A denotes area of cross section of wire. Diameter = 0.2mm, Hence radius=diameter/2=0.2/2=0.1mm=0.1/1000 m. 10=P(1/(22/7)*(0.1/1000)*(0.1/1000)) 10=P(1/3.1415*10^-8) Here ^ stands for power of index. P=3.1415*10^-7...
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R=P(l/A), R denotes resistance of wire P denotes resistivity, l denotes length of wire, A denotes area of cross section of wire. Diameter = 0.2mm, Hence radius=diameter/2=0.2/2=0.1mm=0.1/1000 m. 10=P(1/(22/7)*(0.1/1000)*(0.1/1000)) 10=P(1/3.1415*10^-8) Here ^ stands for power of index. P=3.1415*10^-7 ohm-m. read less
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