What tuition is suggested in class 9 and 10?

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Tutor

Maths and science tuition is required
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Tutor

Reach out to me, I will help you with tuitions for specific subjects
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Guide, Friend, Mentor

Only Maths and maybe physics.. If ICSE board, guidance in English is required. Shakespearan English is taught in icse ..Hence it is required.
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Tutor

only maths tution but if you want to go for science stream in future then you have to take science tuitions also as the basic starts from 9th.
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Tutor

math nd science
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Only Maths and maybe physics, chemistry... If ICSE board, guidance in English is required. Shakespearan English is taught in icse ..Hence it is required.
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Bar Chart:- The columns are positioned over a label that represents a categorical variable. The height of the column indicates the size of the group defined by the categories. Histogram:- The columns...
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Vivek
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Find three numbers in A.P. whose sum is 21 and their product is 231.
Let, three numbers are (a-d), a, (a+d) So, (a-d)+a+(a+d)=21 => a=7 Again, (7-d)×7×(7+d)=231 => (7-d)×(7+d)=231÷7 => 7^2 - d^2 = 33=> d^2 = 49 - 33=> d^2 = 16=> d = 4 So, the numbers are 7-4= 3, 7 and 7+4=11
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Laxmi
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Find the zeroes of the quadratic polynomial x2 + 5x + 6 and verify the relationship between the zeroes and the coefficients.
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now...
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Rekha
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How much monthly fee for class 10 for 1 subject like Maths in Delhi or NCR?
The best way is to charge as per hour. 300/- per hour will be considered acceptable for parents and you.
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Vishal Ranjan
If A:B = 4:5, B:C = 6:7 and C:D = 14:15, find A:D?
(B/C ) * (C/D)= (6/7) * (14/15) => B/D = 4/5 => (A/B)*(B/D)=(4/5)*(4/5) => A/D = 16/25.
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S.
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X Algebra (Maharashtra board 2020)
Solve √(x/y)= 4 (1/x)+(1/y)= 1/(xy) Solution √(x/y)=4 Squaring both sides x/y=16 x=16y x-16y=0 <-eqn1 (1/x)+(1/y)=1/(xy) ((y+x)/xy)=(1/xy) x+y=1 <-eqn2 Multiply by 16 16x+16y=16...
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