Take Class 10 Tuition from the Best Tutors

- Affordable fees
- 1-1 or Group class
- Flexible Timings
- Verified Tutors

✕

Search in

Follow 3

Answer

airthmetic progression Sn = n/2(2a+(n-1)d) given a=1, d=4-1=3 & Sn = 287 287 = n/2 (2*1 +(n-1) 3) 287*2 = n(2 + 3n - 3) 574 = 2n + 3n^2 - 3n 3n^2 -n - 574 = 0 on solving the quadratic equation using formula n= -b + sq.root(b^2 -4ac) ...

read more airthmetic progression Sn = n/2(2a+(n-1)d) given a=1, d=4-1=3 & Sn = 287 287 = n/2 (2*1 +(n-1) 3) 287*2 = n(2 + 3n - 3) 574 = 2n + 3n^2 - 3n 3n^2 -n - 574 = 0 on solving the quadratic equation using formula n= -b + sq.root(b^2 -4ac) ----------------------- 2a we get n = 14, -41/3 n not equal to -41/3 due to negative nos. n=14 Sn = n/2 (a +l) 287 = 14/2(1 +x) 574 = 14 (1+x) 574 / 14 = 1+x 41 = 1 + x So, x = 41 - 1 x = 40 is the solution read less

1

Comments

X=40 First use the formula of summation of n terms an A.P and get value of n then use formula of nth term of A.P

1

Comments

Solution is: x = 40 Explanation:- The LHS of the given equation is an AP, Let the total no.of terms upto 'x' are N, So now using the suitable formula for sum of AP; (N/2) = S Here, a = 1, d = 3, N = ?, S = 287 So, on putting all these values and solving, we get; N = 14 or N = -82/6 Accepting, N =...

read more Solution is: x = 40

Explanation:-

The LHS of the given equation is an AP,

Let the total no.of terms upto 'x' are N,

So now using the suitable formula for sum of AP;

(N/2)[ 2a + (N-1)d ] = S

Here, a = 1, d = 3, N = ?, S = 287

So, on putting all these values and solving, we get;

N = 14 or N = -82/6

Accepting, N = 14 (being a natural number)

Further to solve the value of 'x' , using the formula for finding Nth term of an AP;

T = a + (N-1)d

Here, T= x, N = 14,

Therefore, on solving, we get;

x = 40

read less 0

Comments

View 1 more Answers

Related Questions

Name the quadrant where the sign (-, +)?

In the 2nd quadrant. Where X will be negative and Y will be positive.

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a QuestionRecommended Articles

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Find Class 10 Tuition near you

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you X ### Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

- Select the best Tutor
- Book & Attend a Free Demo
- Pay and start Learning

The best Tutors for Class 10 Tuition Classes are on UrbanPro