Find the smallest number which when increased by 20 is exactly divisible by 90 and 144.

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LCM of 90 and 144 is 720. Hence the required number is 720-20 = 700 Ans
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700
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Lcm of 90 and 144 is= 720,it is the smallest number that is divisible by 90 and144. So number is = 700 answer which is increased by 20 will be 720.
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700.
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