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Find the frequency of a wave whose time period is 0.002 second.

Neet Physics Tutor

Frequency = 1/(Time period) f = 1 0.002 = 500 per Sec

ƒrequency =1/time period Therefore frequency = 1/0.002=1000/2=500 Hz where 1Hz = 1 per second

Tutor

Given -> Time Period=0.002sec -> Formula=> Frequency=1 Time Period F=1 0.002 =(1x1000) (0.002x1000) =1000 2=500Hz => Frequency of wave = 500Hz

Professional Teacher

We know frequency = 1 / Time period That is F = 1/T Given T (time period ) is 0.002 Put it in formulae F=1/0.002 =(1×1000)/2 =500 Hz So frequency of a wave whose time period is 0.002 second is 500 Hz.

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