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Find the frequency of a wave whose time period is 0.002 second.

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IIT-JEE, NEET Physics Faculty with 14 year's experience

Frequency = 1/(Time period) f = 1÷0.002 = 500 per Sec
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ƒrequency =1/time period Therefore frequency = 1/0.002=1000/2=500 Hz where 1Hz = 1 per second
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Given -> Time Period=0.002sec -> Formula=> Frequency=1÷Time Period F=1÷0.002 =(1x1000)÷(0.002x1000) =1000÷2 =500Hz => Frequency of wave = 500Hz
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We know frequency = 1 / Time period That is F = 1/T Given T (time period ) is 0.002 Put it in formulae F=1/0.002 =(1×1000)/2 =500 Hz So frequency of a wave whose time period is 0.002 second is 500 Hz.
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