UrbanPro

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream.

Asked by Last Modified  

1 Answer

+1

Follow 1
Answer

Please enter your answer

Math Magician

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR ...
read more
Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR X=6 km/hour speed of stream read less
Comments

Related Questions

What is linear algebra?
Linear algebra is a branch of mathematics that deals with linear equations, vectors, matrices, and linear transformations. It is a fundamental subject in mathematics, with applications in many areas of science, engineering, and economics.
Archit
0 0
8
Why does "algebraic geometry" have geometry in its name?
Algebraic geometry have geometry in its name due to the word "geometry" in the name "algebraic geometry" reflects the fact that these geometric objects are the primary focus of the subject. Algebraic geometry...
Mangesh
0 0
7
Define limit of the class and class interval?
Normally 1 hour per day, 3 Hour per day on Saturday and Sunday.
Mukesh
How can I score good percentage in my class 10 CBSE boards exam?
Do regular study and stay focused. Read and revised theory and numerical at regular intervals. Work hard on the weak subject and if required take tuition of that subject. NCERT books reading is very important...
Sharmistha
0 0
6

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons





VOLUME OF THE CUBE
If edge(side) of the cube = x cm Then Volume of the Cube= (x)3 Ex:- If edge(side) of the cube = x = 5cm Then Volume of the Cube= (x)3 = (5 )3=125 cm3

Recommended Articles

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more