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Michael Thomas

Hebbal, Bangalore, India - 560024

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# Michael Thomas

## Tutor

Hebbal, Bangalore, India - 560024.

5.0

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## Overview

I have experience teaching through various classes from 5th to BTech students. I follow this profession as I enjoy teaching.Most of my teaching experience comes from voluntary activities during my college days. I have strong applied knowledge of Science and Mathematics and I try to set the foundations rights for the students for their future studies and career choices.
I am working as a Data Scientist having deep knowledge on statistics, machine learning and data science.

## Languages Spoken

Malayalam Mother Tongue (Native)

English Proficient

Tamil Basic

## Education

Indian Insitiute Of Technology, Madras 2019

Bachelor of Technology (B.Tech.)

RT Nagar

Hebbal, Bangalore, India - 560024

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Engineering Entrance Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

1

Engineering Entrance Exams

BITSAT Coaching Classes

Type of class

Crash Course

## Reviews

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No Reviews yet! Be the first one to Review

## FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Data Science, Deep Learning, Engineering Entrance Coaching and Python Training Classes.

2. Do you provide a demo class?

Yes, I provide a paid demo class.

3. How many years of experience do you have?

I have been teaching for 1 year.

## Answers by Michael Thomas (8)

Answered on 02/08/2019 CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1

If evaluate: (ii) ...more
If $cot\Theta&space;=\frac{7}{8}$ evaluate:

$(i)&space;\frac{(1+sin\Theta&space;)(1-sin\Theta&space;)}{(1+cos\Theta)(1-cos\Theta&space;)}$

(ii) $cot^{2}\Theta$

i) Theorems used: ...more

i)$\frac{(1-sin&space;\theta)(1+sin&space;\theta)}{(1-cos&space;\theta)(1+cos&space;\theta)}&space;=&space;\frac{1-&space;sin^2&space;\theta}{1-cos^2&space;\theta}&space;=&space;\frac{cos^2&space;\theta}{sin^2&space;\theta}&space;=&space;cot^2&space;\theta&space;=&space;\frac{49}{64}$

Theorems used:

$\\&space;i)&space;(a+b)(a-b)&space;=&space;a^2&space;-&space;b^2&space;\\&space;ii)&space;1-&space;sin^2&space;\theta&space;=&space;cos^2&space;\theta\\&space;iii)1-&space;cos^2&space;\theta&space;=&space;sin^2&space;\theta$

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Let ABCD be a parallelogram. Let P be the point where diagonal AC and BD. Let AC = BD. Then from property of parallelogram (diagonals bisect each other), AP = PC = PD = BP. Consider traingle APD. AP = DP, hence it is a isoceles triangle. Thus Angle DAP and PDA are are equal. Similarly Angle PCB and PBC... ...more

Let ABCD be a parallelogram. Let P be the point where diagonal AC and BD.

Let AC = BD. Then from property of parallelogram (diagonals bisect each other), AP = PC = PD = BP.

Consider traingle APD. AP = DP, hence it is a isoceles triangle. Thus Angle DAP and PDA are are equal.

Similarly Angle PCB and PBC are equal.

Angle APD and Angle CPB are equal (Opposite angles of intersecting lines)

Hence, Angles DAP, ADP, PCB, PBC are equal.

Similarly Angles PDC, PCD, PAB, PBA are equal.

But Angle PAB = Angle PCD. Interior alternate anlges of line interecting parallel lines.

Thus all the angles are equal and are right angle.

Rectangle is a parallelogram with all angles are right angles.

Dislike Bookmark

Answered on 02/08/2019 CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1

Just draw a triangle. From secant we know cosine is 12/13. Thus adjacent side is a multiple of 12 (12x)and Hypotenuse is a multiple of 13 (13x). Using pythagoras theorem, opposite side has length of 5x. Just plug these values and find them. sine = 5/13 cosine = 12/13 tangent =5/12 cotangent =12/5 cosecant... ...more

Just draw a triangle. From secant we know cosine is 12/13. Thus adjacent side is a multiple of  12 (12x)and Hypotenuse is a multiple of  13 (13x). Using pythagoras theorem, opposite side has length of 5x.

Just plug these values and find them.

sine = 5/13

cosine = 12/13

tangent =5/12

cotangent =12/5

cosecant =13/5

Dislike Bookmark

ABCD is a rhombus. Show that diagonal AC bisects ∠ A as well as ∠ C and diagonal BDbisects ∠... ...more
ABCD is a rhombus. Show that diagonal AC bisects ∠ A as well as ∠ C and diagonal BD
bisects ∠ B as well as ∠ D.

Rhombus is a parallelogram with all sides of the same length.Just consider diagonal AC. It is intercept of two parallel lines. Thus the alternate interior sides are equal. Hence Angle CAB and Angle ACD are equal. Triangle ABC is an isosceles triangle. Thus Angle BAC and Angle BCA are equal.Combining... ...more

Rhombus is a parallelogram with all sides of the same length.
Just consider diagonal AC. It is intercept of two parallel lines. Thus the alternate interior sides are equal. Hence Angle CAB and Angle ACD are equal.
Triangle ABC is an isosceles triangle. Thus Angle BAC and Angle BCA are equal.
Combining both we get Angle ACB, and Angle ACD is equal. Thus Diagonal AC bisects Angle C.
Similar are all the rest.

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Mitochondria
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Engineering Entrance Coaching classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Engineering Entrance Coaching classes

1

Engineering Entrance Exams

BITSAT Coaching Classes

Type of class

Crash Course

Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

1

Board

State, ISC/ICSE, CBSE, IGCSE

ISC/ICSE Subjects taught

Mathematics, Chemistry, Computer Science, Physics

CBSE Subjects taught

Chemistry, Mathematics, Computer Science, Physics

IGCSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

No

State Syllabus Subjects taught

Statistics, Computer Science, Mathematics, Chemistry, Physics

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

1

Board

State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Mathematics, Chemistry, Computer Science, Physics

CBSE Subjects taught

Chemistry, Mathematics, Computer Science, Physics

Taught in School or College

No

State Syllabus Subjects taught

Statistics, Computer Science, Mathematics, Chemistry, Physics

Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

1

Board

State, CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Computer Application, Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Python Training classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Python Training classes

1

Course Duration provided

1-3 months

Seeker background catered to

Corporate company, Individual, Educational Institution

Certification provided

No

Python applications taught

Machine Learning with Python, Help in assignment, Text Processing with Python, Data Visualization with Python, Automation with Python , Data Science with Python, Data Analysis with Python , Data Extraction with Python , Regular Expressions with Python

Data Science Classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Data Science Classes

1

Data science techniques

Machine learning, Artificial Intelligence, Python

Deep Learning Training 5.0

Class Location

I am Willing to Travel

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Deep Learning Training

1

Deep_Learning_Techniques

Tensorflow, Python

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No Reviews yet! Be the first one to Review

## Answers by Michael Thomas (8)

Answered on 02/08/2019 CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1

If evaluate: (ii) ...more
If $cot\Theta&space;=\frac{7}{8}$ evaluate:

$(i)&space;\frac{(1+sin\Theta&space;)(1-sin\Theta&space;)}{(1+cos\Theta)(1-cos\Theta&space;)}$

(ii) $cot^{2}\Theta$

i) Theorems used: ...more

i)$\frac{(1-sin&space;\theta)(1+sin&space;\theta)}{(1-cos&space;\theta)(1+cos&space;\theta)}&space;=&space;\frac{1-&space;sin^2&space;\theta}{1-cos^2&space;\theta}&space;=&space;\frac{cos^2&space;\theta}{sin^2&space;\theta}&space;=&space;cot^2&space;\theta&space;=&space;\frac{49}{64}$

Theorems used:

$\\&space;i)&space;(a+b)(a-b)&space;=&space;a^2&space;-&space;b^2&space;\\&space;ii)&space;1-&space;sin^2&space;\theta&space;=&space;cos^2&space;\theta\\&space;iii)1-&space;cos^2&space;\theta&space;=&space;sin^2&space;\theta$

Dislike Bookmark

Let ABCD be a parallelogram. Let P be the point where diagonal AC and BD. Let AC = BD. Then from property of parallelogram (diagonals bisect each other), AP = PC = PD = BP. Consider traingle APD. AP = DP, hence it is a isoceles triangle. Thus Angle DAP and PDA are are equal. Similarly Angle PCB and PBC... ...more

Let ABCD be a parallelogram. Let P be the point where diagonal AC and BD.

Let AC = BD. Then from property of parallelogram (diagonals bisect each other), AP = PC = PD = BP.

Consider traingle APD. AP = DP, hence it is a isoceles triangle. Thus Angle DAP and PDA are are equal.

Similarly Angle PCB and PBC are equal.

Angle APD and Angle CPB are equal (Opposite angles of intersecting lines)

Hence, Angles DAP, ADP, PCB, PBC are equal.

Similarly Angles PDC, PCD, PAB, PBA are equal.

But Angle PAB = Angle PCD. Interior alternate anlges of line interecting parallel lines.

Thus all the angles are equal and are right angle.

Rectangle is a parallelogram with all angles are right angles.

Dislike Bookmark

Answered on 02/08/2019 CBSE/Class 10/Mathematics/UNIT V: Trigonometry/Introduction to Trigonometry/NCERT Solutions/Exercise 8.1

Just draw a triangle. From secant we know cosine is 12/13. Thus adjacent side is a multiple of 12 (12x)and Hypotenuse is a multiple of 13 (13x). Using pythagoras theorem, opposite side has length of 5x. Just plug these values and find them. sine = 5/13 cosine = 12/13 tangent =5/12 cotangent =12/5 cosecant... ...more

Just draw a triangle. From secant we know cosine is 12/13. Thus adjacent side is a multiple of  12 (12x)and Hypotenuse is a multiple of  13 (13x). Using pythagoras theorem, opposite side has length of 5x.

Just plug these values and find them.

sine = 5/13

cosine = 12/13

tangent =5/12

cotangent =12/5

cosecant =13/5

Dislike Bookmark

ABCD is a rhombus. Show that diagonal AC bisects ∠ A as well as ∠ C and diagonal BDbisects ∠... ...more
ABCD is a rhombus. Show that diagonal AC bisects ∠ A as well as ∠ C and diagonal BD
bisects ∠ B as well as ∠ D.

Rhombus is a parallelogram with all sides of the same length.Just consider diagonal AC. It is intercept of two parallel lines. Thus the alternate interior sides are equal. Hence Angle CAB and Angle ACD are equal. Triangle ABC is an isosceles triangle. Thus Angle BAC and Angle BCA are equal.Combining... ...more

Rhombus is a parallelogram with all sides of the same length.
Just consider diagonal AC. It is intercept of two parallel lines. Thus the alternate interior sides are equal. Hence Angle CAB and Angle ACD are equal.
Triangle ABC is an isosceles triangle. Thus Angle BAC and Angle BCA are equal.
Combining both we get Angle ACB, and Angle ACD is equal. Thus Diagonal AC bisects Angle C.
Similar are all the rest.

Dislike Bookmark

Mitochondria
Dislike Bookmark

Michael Thomas describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Michael is located in Hebbal, Bangalore. Michael takes at students Home. He has 1 years of teaching experience . Michael has completed Bachelor of Technology (B.Tech.) from Indian Insitiute Of Technology, Madras in 2019. He is well versed in Tamil, English and Malayalam.

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