I have an experience taking tution over 3 years.
Will make my student to enjoy and understand the basic idea of the subject.
I was taking tution in Adyar, currently, I have been relocated to Velacherry.
I have the passion to teach.
Velachery, Chennai Details verified of Mahalakshmi S.✕
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Madras university 2011
Bachelor of Science (B.Sc.)
Velachery, Chennai, India - 600042
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
State, CBSE
Experience in School or College
Home tution
Subjects taught
Electronics, Chemistry, Physics, Mathematics, Accountancy, English, Tamil
Taught in School or College
Yes
Teaching Experience in detail in Class 12 Tuition
I have taken tution at my home for classes 1_12 Maths and science for 3 years. Individual care will be given. Make the student to understand the basics.
Answered on 13/05/2020 Learn CBSE - Class 11/Mathematics/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
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((1(1+i)-2(1-4i))/((1-4i)(1+i))*((3-4i)/(5+i))
((1+i-2+8i)/(1+i-4i-4i^2))*((3-4i)/(5+i))
i^2=-1
((-1+9i)/(1-3i+4))*((3-4i)/(5+i))
((-1+9i)/(5-3i))*((3-4i)/(5+i))
(-3+4i+27i-36i^2)/(25+5i-15i-3i^2)
(-3+31i+36)/(25-10i+3)
((33+31i)/(28-10i))((28+10i)/(28+10i))
(924+330i+858i+310i^2)/((28)^2-(10i)^2) [(a+b)(a-b)=a^2-b^2]
(924-310+330i+868i)/(784+100)
(614+1198i)/884
Taking 2 out of the fraction
2(307+599i)/2(442)
(307+599i)/442
(307/442)+(599i/442)
Like 0 
Answers 18 
Comments Answered on 13/05/2020 Learn CBSE - Class 11/Mathematics/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
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Post a Lesson
Let z1= x+iy --(1)
z2=a+ib --(2)
Rez1=x --(3) Imz1=y --(5)
Rez2=a --(4) Imz2=b --(6)
From (1&2) z1z2=(x+iy)(a+ib)
=xa+ixb+iya+i^2yb. (i^2=-1)
= xa+ixb+iya-yb
=xa-yb + i(xb+ya)
Re(z1z2)= xa-yb -- LHS
from(3,4,5&6)
Rez1Rez2-Imz1Imz2 = xa-yb --- RHS
LHS = RHS .Hence Proved.
Like 0 Answers 48 Comments Ask a Question
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
State, CBSE
Experience in School or College
Home tution
Subjects taught
Electronics, Chemistry, Physics, Mathematics, Accountancy, English, Tamil
Taught in School or College
Yes
Teaching Experience in detail in Class 12 Tuition
I have taken tution at my home for classes 1_12 Maths and science for 3 years. Individual care will be given. Make the student to understand the basics.
Answered on 13/05/2020 Learn CBSE - Class 11/Mathematics/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
Ask a Question
Post a Lesson
((1(1+i)-2(1-4i))/((1-4i)(1+i))*((3-4i)/(5+i))
((1+i-2+8i)/(1+i-4i-4i^2))*((3-4i)/(5+i))
i^2=-1
((-1+9i)/(1-3i+4))*((3-4i)/(5+i))
((-1+9i)/(5-3i))*((3-4i)/(5+i))
(-3+4i+27i-36i^2)/(25+5i-15i-3i^2)
(-3+31i+36)/(25-10i+3)
((33+31i)/(28-10i))((28+10i)/(28+10i))
(924+330i+858i+310i^2)/((28)^2-(10i)^2) [(a+b)(a-b)=a^2-b^2]
(924-310+330i+868i)/(784+100)
(614+1198i)/884
Taking 2 out of the fraction
2(307+599i)/2(442)
(307+599i)/442
(307/442)+(599i/442)
Like 0 Answers 18 Comments Answered on 13/05/2020 Learn CBSE - Class 11/Mathematics/Mathematics/Unit-II: Algebra/Complex Numbers and Quadratic Equations/NCERT Solutions/Miscellaneous Exercise 5
Ask a Question
Post a Lesson
Let z1= x+iy --(1)
z2=a+ib --(2)
Rez1=x --(3) Imz1=y --(5)
Rez2=a --(4) Imz2=b --(6)
From (1&2) z1z2=(x+iy)(a+ib)
=xa+ixb+iya+i^2yb. (i^2=-1)
= xa+ixb+iya-yb
=xa-yb + i(xb+ya)
Re(z1z2)= xa-yb -- LHS
from(3,4,5&6)
Rez1Rez2-Imz1Imz2 = xa-yb --- RHS
LHS = RHS .Hence Proved.
Like 0 Answers 48 Comments Ask a Question
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