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I am Chemistry Teacher with 18 years of rich experience in teaching CBSE/ICSE/ISC/IB curriculum.I teach and guide 9th-12th grade students who are preparing for IIT-JEE,NEET,IIT(FOUNDATIO),OLYMPIAD and intermediate board examinations.I worked as a chemistry teacher in reputed colleges and helped students in cracking Engineering and Medical Entrance Examinations both at STATE and NATIONAL LEVELS.Through my systematic and concept-based teaching methodology any student can learn and excel in CHEMISTRY .I encourage you to go through my students testimonials to know more about me and my teaching methodology Produced ranks many ranks in ENGINEERING AND MEDICAL and many of my students are placed IIT'S AND MEDIAL COLLEGES in INDIA I believe in Concept to Core Teaching of chapter being organic or inorganic or physical chemistry.
I have been a Prof in MS Ramiah College of Engg in Bangalore having taught students for more than 5 years
I am working as a tutor since 2010 in Pune. I have 5 years of teaching experience. I have completed M tech + BTech from IIT and presently pursuing PhD. I am a pure IITian. Many of my passed out students are now placed in IITs and NITs. Presently I am also working as Asst Professor in a reputed Engineering College.
I have more than 3 years teaching experience. I am sure I can make Physics easy for you. I will quote the price after talk to the candidate.
Physics as a subject requires deep understanding for the concept and thinking in all possible dimensions to solve a given problem . As a senior physics faculty I give more emphasis on concept building and the types of questions that can be formed on that concept . In my opinion if the student is good in concept understanding he can solve any problem based on that. As a master in field I know the areas from where the questions are mould and prepare students in such a way that they can handle the pressure in exam without losing cool. I have specially designed the module in which all variety of questions based on their types are covered level by level so that the student could get the idea of complex nature of problem and the right approach to solve any particular problem in given time.
I have completed my B.Tech from IIT Kanpur in 2009. I guarantee 100% selection in IIT for my students. Please contact me directly to know the detailed plan and a free demo. Being an IIT Alumni myself, I have developed numerous unique methods of problem resolution especially for competitive exams. Due to my interest in the field of teaching, I have been associated with the leading educational institutes in India from the past 6 years. From about 1 year, I am working as a freelance tutor and have guided many students to the top institutes of India. Contact me for tips & tricks that would guarantee your selection.
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Answered on 16 Oct Exam Coaching/CET Coaching/Biology
Sec (90×1+30)
= - Cosec30
= - 2
Rakesh Kumar Singh
Tutor
Lesson Posted on 21 Sep CBSE/Class 11/Science/Mathematics CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Permutations and Combinations Exam Coaching/CET Coaching/Mathematics
Om Prakash Mishra
I am teaching Mathematics and Physics from past more than 12 years in coaching as well as home tuition...
Permutation means arrangement
Fundamental principles of counting
If a work can be done in m ways and the either can be done in n ways, then the no .of ways in which both the works can be done is m×n ways.
But if they are done I depend on each other that is doing of one does not affect the other, then it is m+n.
The no of ways in which n different things can be arranged is n! Which is equal to
n!=n ×(n-1)×.....×2×1.
The no. of ways in which r things out of n things can be arranged is
n^P^r = n!/(n-r)!.
If any particular object is repeated p, q.. times then the result is divided by p! q!... respectively to get the desired permutation.
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Lesson Posted on 25 Sep CBSE/Class 11/Science/Mathematics/Unit-II: Algebra/Permutations and Combinations IIT JEE/IIT JEE MAINS IIT JEE/IIT - JEE Mains/Mathematics/Permutations and Combinations
Om Prakash Mishra
I am teaching Mathematics and Physics from past more than 12 years in coaching as well as home tuition...
When things are arranged in a circle then number of permutations ( arrangements ) is calculated in the following way :
Since one of the objects is always fixed in its position so the total number of objects to be arranged gets reduced by 1.
So if total n objects are there then no of permutations will be
(1) when clockwise and anticlockwise permutations are counted different = (n-1)!
(2) when clockwise and anticlockwise are not counted different = (n-1)!/2
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