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C Language > Learn C Language > Why doesn't auto evaluate as an rvalue reference when...
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Why doesn't auto evaluate as an rvalue reference when a temporary is given in C++?

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Oracle, Hindi, C++, C, MS Office, VBScript,JavaScript,Spoken English etc with 31 years of experience

The type of an expression is never a reference type, but references produce glvalue expressions, whereas non-reference types can also produce prvalue (“pure values”)
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