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Can a function defined inside another function?

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Doing mathematics & computing from IIT Delhi

No, you can call other function(s) inside a function but you cannot define a new function in it.
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ya why not you can have following example Double stuff(double a, double b) { struct parameters { double a, b; }; double f(double x, void * params) { struct parameters p=(struct parameters *) params; double a=p->a, b=b->b; return some_expression_involving(a,b,x); ...
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ya why not you can have following example Double stuff(double a, double b) { struct parameters { double a, b; }; double f(double x, void * params) { struct parameters p=(struct parameters *) params; double a=p->a, b=b->b; return some_expression_involving(a,b,x); } struct parameters par = {a,b}; return integrate(&f, &par); // return added! } read less
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In standard C No, but some compilers do, example gcc
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I am a teacher.

Yes, you can. See below example: display() function definition inside sum() function definition. #include "stdio.h" void main(){ sum(); } int sum(){ void display(){ printf("inside display"); } printf("inside sum \n"); display(); }
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Tutor

Yes . It is called function within a function.
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Programming Trainer

Yes, but the prototype of the function must be declared in the begging of the program. Another notable point is that it will re defined every time the outer function is called and it might lead the compiler to be ambiguous about such lines of code.
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Thanks for the question Kamal, No a function cannot be defined inside another function. Thanks, Team DishaaPro www.dishaapro.com
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Professional Trainer:: Hadoop Big Data, DevOps, Perl, Python

No its not allowed, but some compilers support. Instead check out OOP C++, which would encapsulation, that is better than function in function.
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